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3 years ago

Combine like terms to create an equivalent expression. -2/3a + 5/6a - 1/6

Mathematics

1 answer:

Neko [114]3 years ago

4 0

Yup, they were right Combined like terms

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17.The diameter of a circle has endpoints P(–7, –10) and Q(3, 2).

ser-zykov [4K]

A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
10^2+12^2=244
r=2(61)^(1/2)
c.)(x+2)^2+(y+4)^2=244

7 0

4 years ago

Simplify the expiration 2h+6h+4h

dezoksy [38]

Answer:

I think the answer is12h?

6 0

3 years ago

Answers and the work for them please

Anon25 [30]

Answer:

The screen is black? there is nothing there

Step-by-step explanation:

this is nonsense man

3 0

3 years ago

On a math test 12 students earned an a this number is exactly 25% of the total number of students in the class how many students

statuscvo [17]

Answer:

48 students.

Step-by-step explanation:

25% of total students = 12

suppose,

total students= x

so,

25% of x=12

(25/100)*x=12

25*x=(12*100)

x=1200/25

x=48

therefore,

x= total students= 48.

7 0

3 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

romanna [79]

Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

3 0

3 years ago