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2 years ago

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Mathematics

1 answer:

Anarel [89]2 years ago

3 0

Answer:

A shirt rack contains 5 striped shirts, 8 solid shirts, and 6 polka dot shirts. How many outcomes are there when choosing a shirt from the rack?

Step-by-step explanation:

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- 40 = -5r (algebra)

Gekata [30.6K]

Answer:

r=8

hope this helps

have a good day :)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the lowest terms<br> fraction that's equal<br> to 0.33.

irinina [24]

The answer is 33/100

5 0

3 years ago

Read 2 more answers

Kelly is knitting a scarf for her brother. It took her 2/3 hour to knit 5/6 foot of the scarf. How fast is Kelly's knitting spee

juin [17]

Answer:

C. 4/5 feet per hour

Step-by-step explanation:

All you wanna do is to divide 2/3 and 5/6

then you'll have 4/5

Hoped this helps!

4 0

3 years ago

HELPPPPPPPPP i have the most trouble with math what’s the answer??

lakkis [162]

Answer:

Second Option

$\frac{5\sqrt{11} +5\sqrt{3}}{8}$

Step-by-step explanation:

To simplify the expression you must multiply the numerator and the denominator of the fraction by the conjugate of the denominator.

If you have an expression of the form

$a -b$ then its conjugate will be $a + b.$

The result of that multiplication will be

$a ^ 2 -b ^ 2$

Therefore we have the expression

$\frac{5}{\sqrt{11} -\sqrt{3}}$

By multiplying by the conjugate of the denominator we have

$\frac{5}{\sqrt{11} -\sqrt{3}}*\frac{\sqrt{11} +\sqrt{3}}{\sqrt{11} +\sqrt{3}}\\\\\\\frac{5(\sqrt{11} +\sqrt{3})}{(\sqrt{11})^2 -(\sqrt{3})^2}\\\\\\\frac{5\sqrt{11} +5\sqrt{3}}{11 -3}\\\\\\\frac{5\sqrt{11} +5\sqrt{3}}{8}$

6 0

3 years ago

A circular garden has a circumference of

omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: $2\pir$ . A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

$d\pi$

So, solving for both the radius and the diameter gives us:

$d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2$

So, the length of thes traight path that goes through the center of the guardain is just $8xy^2$ , and we can use the radius for the next part of the problem.

The area of a circle is $\pi r^2$ , which means we can just plug in the radius and find our area:

$A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4$

So, we have found our area( $16 \pi x^2 y^4$ ) and the problem is done.

6 0

3 years ago