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astraxan [27]
3 years ago
12

Use the distributive property to remove the parenthesis 2=(v-8)

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

Answer:

v = 10

Step-by-step explanation:

2 = v - 8

add 8 to both sides

10 = v

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At a gymnastics meet, twenty gymnasts compete for first, second, and third place. How many ways can first, second, and third pla
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Part A:

Given that a<span>t a gymnastics meet, twenty gymnasts compete for first, second, and third place. The number of ways </span><span>first, second, and third place can be assigned</span><span> is given by

^{20}P_3= \frac{20!}{(20-3)!}  \\  \\ = \frac{20!}{17!} =20\times19\times18 \\  \\ =6,840\ ways



Part B:

</span>Given that at a gymnastics meet, twenty gymnasts compete for first, second, and third place. If the t<span>hird place has been announced the number of ways that the remaining two places can be assigned</span> is given by :

<span>^{19}P_2= \frac{19!}{(19-2)!}  \\  \\ = \frac{19!}{17!} =19\times18 \\  \\ =342\ ways
</span>


Part C:

Given that at a gymnastics meet, twenty gymnasts compete for first, second, and third place. If the third and second places have been announced the number of ways that the <span>first place</span> can be assigned is given by :

^{18}P_1= \frac{18!}{(18-1)!}  \\  \\ = \frac{18!}{17!} =18\ ways
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3 years ago
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Use the following area model to multiply 42 x 73
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Give the coordinates of the image. ​
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Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

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Answer:

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Step-by-step explanation:

not sure

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