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2 years ago

Simplify. x + y - 0 x 2 - y 2

Mathematics

1 answer:

dusya [7]2 years ago

3 0

Answer:

-y^(2)+x+y

Step-by-step explanation:

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2.75j + 2.25 - 1.5j + 3 simplified

sergiy2304 [10]

You can say 2.75j - 1.5j = 1.25j and 2.25+3 = 5.25 so now you have :
1.25j + 5.25 and thats simplify :)))
i hope this is helpful
have a nice day

4 0

3 years ago

Read 2 more answers

The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t

AURORKA [14]

<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

As in the statement:

<em>The distance form</em> $(0,0)$ to $(0,2)$ is $\sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2$ <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from $(0,0) \ to \ (1,\sqrt{2})$ whose result is also 2 and is the radius of the circle.

3 0

2 years ago

Read 2 more answers

Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3

vagabundo [1.1K]

Answer:

not

Step-by-step explanation:

$\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=$

First is A and Second is B

Let's find A*B

$\left[\begin{array}{ccc}-2(-2)+4*3&-2*1+4*7\\1(-2)+3*3&1*1+3*7\end{array}\right] =\left[\begin{array}{ccc}16&26\\7&22\end{array}\right]$

$\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right] \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =$

Now let's find B*A

$\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]$

c) They are not

7 0

2 years ago

Find the inverse of the function f(x) = (x - 4) 2 - 5 if x ≥ 4.

Serggg [28]

Same here, we do a quick switcharoo on the variables first,

$\bf \stackrel{f(x)}{y}=(x-4)^2-5\qquad inverse\implies \boxed{x}=\left( \boxed{y}-4 \right)^2-5
\\\\\\
x+5=(y-4)^2\implies \pm\sqrt{x+5}=y-4\implies \pm\sqrt{x+5}+4=y$

6 0

2 years ago

I will mark as brainliest:)

Aliun [14]

Answer:

Cube C

Step-by-step explanation:

${ \sf{because \: it \: is \: identical}}$

8 0

2 years ago