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kipiarov [429]
3 years ago
6

Letter=number 14.6=e-3.2

Mathematics
2 answers:
dedylja [7]3 years ago
5 0
The answer is e = 17.8. Hope this helps!
barxatty [35]3 years ago
3 0

Answer: e = 17.8

Step-by-step explanation: 14.6 + 3.2

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What is the value of the expression?<br>A. 3<br>B. 12<br>C. 27<br>D. 81​
Aleksandr [31]
I think the answer a
6 0
3 years ago
Read 2 more answers
Can someone please help me????? Please I'm not good with Geometry
Otrada [13]

The hurdle and runner form a right triangle (see attached picture) such that

sin(30°) = <em>h</em> / (5 ft)

and

cos(30°) = <em>x</em> / (5 ft)

where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So

<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft

<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft

6 0
3 years ago
6 × 3 − (4 × 3) + 16 ÷ 4 = 11
rjkz [21]

Answer:

2

Step-by-step explanation:

6x3 = 18

4x3 = 12

18 - 12 = 6

16 / 4 = 4

6 - 4 = 2

4 0
3 years ago
The sum of 9and -16 increased by 4
LenaWriter [7]

Answer:

-3

Step-by-step explanation:

The statement is,

→ Sum of 9 and -16 increased by 4

The equation will be,

→ {9 +(-16)} + 4

→ (9 - 16) + 4

→ -7 + 4

→ [ -3 ]

Hence, the solution is -3.

7 0
2 years ago
Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a
Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = \frac{1}{6}

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

E(X)=\sum x\cdot P(X=x)

Compute the expected monetary value of a single roll as follows:

E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17

Thus, the expected monetary value of a single roll is $1.17.

7 0
3 years ago
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