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3 years ago

Simplify this plz thanks

Mathematics

1 answer:

viva [34]3 years ago

5 0

Answer:

$\frac{1}{g^{5nd+10v+20dv} }$

Step-by-step explanation:

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Subtract. Write your answer in simplest form.

hichkok12 [17]

Answer:

No. it would be 4 3/14

Step-by-step explanation:

5-1=4

common denominator is 14 to get there,

1x7=7

2x7=14

2x2=4

7x2=14

7/14 - 4/14 = 3/14

put it all back together and you get 4 3/14

7 0

3 years ago

What is the approximate area of the shaded sector in the circle shown below?

forsale [732]

Answer:

where is the picture...

6 0

3 years ago

Read 2 more answers

PROBLEM SOLVING When a plant or animal dies, it stops acquiring carbon-14 from the atmosphere. The amount y in grams) of carbon-

kykrilka [37]

Answer:

0.01%

Step-by-step explanation:

y=a (0.5)^t/5730

y=a [(0.5)^t/5730]

when you put 0.5^1/5730

it'll give you 0.99

The "equation" is y=a(1-r)^t

so 1-0.99 is 0.01

4 0

3 years ago

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

3 years ago

The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term

sashaice [31]

Answer:

Hello,

Step-by-step explanation:

$Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}$

5 0

3 years ago