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Kitty [74]
3 years ago
10

Simplify this plz thanks

Mathematics
1 answer:
viva [34]3 years ago
5 0

Answer:

\frac{1}{g^{5nd+10v+20dv}  }

Step-by-step explanation:

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Subtract. Write your answer in simplest form.
hichkok12 [17]

Answer:

No. it would be 4 3/14

Step-by-step explanation:

5-1=4

common denominator is 14 to get there,

1x7=7

2x7=14

2x2=4

7x2=14

7/14 - 4/14 = 3/14

put it all back together and you get 4 3/14

7 0
3 years ago
What is the approximate area of the shaded sector in the circle shown below?
forsale [732]

Answer:

where is the picture...

6 0
3 years ago
Read 2 more answers
PROBLEM SOLVING When a plant or animal dies, it stops acquiring carbon-14 from the atmosphere. The amount y in grams) of carbon-
kykrilka [37]

Answer:

0.01%

Step-by-step explanation:

y=a (0.5)^t/5730

y=a [(0.5)^t/5730]

when you put 0.5^1/5730

it'll give you 0.99

The "equation" is y=a(1-r)^t

so 1-0.99 is 0.01

4 0
3 years ago
Question in picture<br><br>A) 16/63<br><br>B)-16/63<br><br>C) 63/16<br><br>D) -63/16
Orlov [11]
ANSWER
\tan(x + y) =  -  \frac{63}{16}


EXPLANATION


We were given that,

\csc(x)  =  \frac{5}{3}

This implies that,

\sin(x)  =  \frac{3}{5}

We use the Pythagorean identity

\sin^{2} (x)  +  \cos^{2} (x)= 1
to get,


\cos(x)  =  \sqrt{1 - ( { \frac{3}{5} })^{2}}  =  \frac{4}{5}


We were also given that,


\cos(y)  =  \frac{5}{13}

This means that,


\sin(y)  =  \sqrt{1 -  {( \frac{5}{13}) }^{2} }  =  \frac{12}{13}

This is because,


0 <  \: x \:  <  \frac{\pi}{2}


0 <  \: y \:  <  \frac{\pi}{2}

This angles are in the first quadrant so we pick the positive values.

\tan(x + y)  =  \frac{ \sin(x + y) }{ \cos(x + y) }


\tan(x + y)  =  \frac{ \sin(x ) \cos(y)   +  \sin(y)  \cos(x) }{ \cos(x) \cos(y)  -  \sin(x)  \sin(y) }



\tan(x + y)  =  \frac{  \frac{3}{5}   \times  \frac{5}{13}  +   \frac{12}{13}   \times  \frac{4}{5}  }{  \frac{4}{5}  \times  \frac{5}{13}   -   \frac{3}{5}  \times  \frac{12}{13}  }



\tan(x + y) =  -  \frac{63}{16}

The correct answer is D
4 0
3 years ago
The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term​
sashaice [31]

Answer:

Hello,

Step-by-step explanation:

Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}

5 0
3 years ago
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