All categories

3 years ago

Simplify this plz thanks

Mathematics

1 answer:

viva [34]3 years ago

5 0

Answer:

$\frac{1}{g^{5nd+10v+20dv} }$

Step-by-step explanation:

You might be interested in

A movie theater has 1000 seats. There are 424 adults and 339 children sitting in seats. How many of the seats are empty

aev [14]

Answer:

237 seats are empty

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Estimate the values to complete the table.

lbvjy [14]

Answer:

Step-by-step explanation:

For angle C,

cos(∠C) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$ = 0.97

sin(∠C) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$ = 0.26

tan(∠C) = $\frac{\text{Adjacent side}}{\text{Adjacent side}}$ = 0.27

Therefore, from the triangle ABC,

cos(∠A) = cos(90° - ∠C)

= sin(∠C)

= 0.26

sin(∠A) = sin(90 - ∠A)

= cos(∠A)

= 0.97

tan(∠A) = $\frac{\text{sinA}}{\text{cosA}}=\frac{0.97}{0.26}$

= 3.73

Angle $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$ $\frac{\text{Opposite side}}{\text{Hypotenuse}}$ $\frac{\text{Opposite side}}{\text{Adjacent side}}$

A 0.26 0.97 3.73

3 0

3 years ago

18. Paul can type 60 words per minute and Jennifer can type 80 words per minute. How does Paul's typing speed compare to Jennife

Serggg [28]

Paul can type fast but 20 words less than Jennifer a minute.

8 0

3 years ago

Read 2 more answers

What is the area of a triangle with vertices at (0, – 2), (8, – 2), and (9, 1)?

Luda [366]

<u>ANSWER: </u>

The area of the triangle with vertices at (0, – 2), (8, – 2), and (9, 1) is 12 square units.

<u>SOLUTION: </u>

Given, vertices of the triangle are A(0, -2), B(8, -2) and C(9, 1).

We have to find the area of the given triangle.

We know that,

$\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)$

$\text { Where, }\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right),\left(x_{3}, y_{3}\right) \text { are vertices of the triangle. }$

Here in our problem, $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(0,-2),\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)=(8,-2) \text { and }\left(\mathrm{x}_{3}, \mathrm{y}_{3}\right)=(9,1)$

Now, substitute the above values in the formula.

$\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)$

$=\frac{1}{2}(0(-2-1)+8(1-(-2))+9(-2-(-2))$

$=\frac{1}{2}(0+8(1+2)+9(2-2))$

$\frac{1}{2}(0 + 0 +24) = \frac{24}{12} = 2$

Hence, the area of the triangle is 12 sq units.

7 0

2 years ago

Find the consecutive integers who's sum is -33

RUDIKE [14]

-17,-16 because
lets say the first integer is x
Then the second integer is x+1
Let's make an equation
x+(x+1)=-33
2x+1=-33
Subtract 1 from both sides
2x=-34
Divide both sides by 2
x=-17
The first number is -17
The second number is -16

6 0

3 years ago