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zhannawk [14.2K]
3 years ago
7

Simpfly by dividing [-5/8] divided by [-3/4]

Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

-5/-6

Step-by-step explanation:

you just need to flip the second one around and multiply across afterwards

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What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2
OverLord2011 [107]

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

If you want to learn more about polynomials:

brainly.com/question/4142886

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2 years ago
True or False. i think this is easy but
inna [77]

Answer:

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Step-by-step explanation:

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3 years ago
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Find the 90 th derivative of the function ƒ(x)=cos(x)
Inessa [10]
F(x) = cos x
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f''(x) = -cos x
f'''(x) = sin x
f''''(x) = cos x

90/4 = 22 Remainder 2
Therefore, 90th derivative of f(x) = cos x is -cos x.
5 0
3 years ago
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