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Ket [755]
3 years ago
5

What is the slope of the line that passes through the points E(5, 1) and F(2, 7)?

Mathematics
2 answers:
s2008m [1.1K]3 years ago
3 0

Answer:

I would say it's B(3/8)

bekas [8.4K]3 years ago
3 0

Answer:

7 - 1/2 - 5 = 6/-3 = -2

Step-by-step explanation:

None of those answers are correct the answer is -2

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How to solve 4n²-3n-7=0
almond37 [142]
4n^2-3n-7=0\\ \\ a=4, \ \ b=-3 \ \ c=-7\\ \\ \Delta = b^{2}-4ac = (-3)^{2}-4*4* (-7)= 9+112=121

x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{ 3-\sqrt{ 121}}{2*4}=\frac{ 3-11}{8}= \frac{-8 }{ 8}=-1 \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{ 3+\sqrt{ 121}}{2*4}=\frac{ 3+11}{8}= \frac{14 }{ 8}= \frac{7}{4}=1\frac{3}{4}


4 0
3 years ago
Read 2 more answers
A container contains 10 diesel engines. the company chooses 8 engines at​ random, and will not ship the container if any of the
lions [1.4K]

Answer:

16/25

Step-by-step explanation:

We just have to find the probability that the 8 non-defects are chosen.

1. Chance first defect is undetected: 8/10 = <em>4/5</em>

2. Chance second defect is undetected: <em>4/5</em>

3. Total probability': 4/5 * 4/5 = 16/25

7 0
3 years ago
The student council sold jars of mixed nuts at their bazaar they were given 40 empty jars. They paid $19.60 for the nuts and $11
Alex Ar [27]

Answer:

\$1.75

Step-by-step explanation:

Total amount paid for the nuts is $19.60

Total amount paid for the ribbons is $11.20

Profit made on each jar is 98¢= $0.98

Cost price of the nuts and ribbon for the 40 jars is 19.6+11.2=\$30.8

Cost price for nuts and ribbonn for one jar = \dfrac{30.8}{40}=\$0.77

Selling price is the sum of the cost price and profit.

Selling price for one jar = 0.77+0.98=\$1.75

They charged \$1.75 for each jar.

3 0
2 years ago
The sum of the squares of two consecutive positive integers is 41. Find the two
Komok [63]

We have to present the number 41 as the sum of two squares of consecutive positive integers.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

16 + 25 = 41

<h3>Answer: 4 and 5</h3>

Other method:

n, n + 1 - two consecutive positive integers

The equation:

n² + (n + 1)² = 41     <em>use (a + b)² = a² + 2ab + b²</em>

n² + n² + 2(n)(1) + 1² = 41

2n² + 2n + 1 = 41     <em>subtract 41 from both sides</em>

2n² + 2n - 40 = 0     <em>divide both sides by 2</em>

n² + n - 20 = 0

n² + 5n - 4n - 20= 0

n(n + 5) - 4(n + 5) = 0

(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0

n = -5 < 0 ∨ n = 4 >0

n = 4

n + 1 = 4 + 1 = 5

<h3>Answer: 4 and 5.</h3>
7 0
2 years ago
Which is closest to the distance between A and B on the number
nata0808 [166]

Answer:

C) 13

Step-by-step explanation:

A on the number line is about -5 and B is 8. Act as if there wasn't a negative sign in front of the 5. Add the two numbers together the get the distance.

7 0
3 years ago
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