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AysviL [449]
3 years ago
8

Find the Greatest Common Factor

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0
First one is 5, second one is 9, third one is 4.

Hope this helps. :)
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1*1*18
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2*3*3


4 0
3 years ago
Read 2 more answers
A complex fraction is equal to a number less than 1 if the denominator is greater than.....
bixtya [17]
If the denominator is greater than nominator.
3 0
3 years ago
True or False​: According to the Order of​ Operations, exponents are applied before the expression in​ parentheses, and addition
faust18 [17]
False because parentheses go first.... just follow PEMDAS
8 0
3 years ago
11. Through (-3,-5), perpendicular to -2x - 5y = -19
Grace [21]

Answer:

11) D. y=5/2x+5/2 , 12) B. y=8/5x+69/5, 14) A. y=-9/5x-67/5

Step-by-step explanation:

11) The function of the perpendicular line can be found in terms of its slope and a given point by this formula:

y-y_{o} = m_{\perp}\cdot (x-x_{o})

Where:

x_{o}, y_{o} - Components of the given point, dimensionless.

m_{\perp} - Slope, dimensionless.

Besides, a slope that is perpendicular to original line can be calculated by this expression:

m_{\perp} = -\frac{1}{m}

Where m is the slope of the original line, dimensionless.

The original slope is determined from the explicitive form of the given line:

-2\cdot x - 5\cdot y = -19

2\cdot x +5\cdot y = 19

5\cdot y = 19 - 2\cdot x

y = \frac{19}{5} -\frac{2}{5}\cdot x

The original slope is -\frac{2}{5}, and the slope of the perpendicular line is:

m_{\perp} = -\frac{1}{\left(-\frac{2}{5}\right) }

m_{\perp} = \frac{5}{2}

If x_{o} = -3, y_{o} = -5 and m_{\perp} = \frac{5}{2}, then:

y-(-5) = \frac{5}{2}\cdot [x-(-3)]

y + 5 = \frac{5}{2}\cdot x +\frac{15}{2}

y = \frac{5}{2}\cdot x +\frac{5}{2}

The right answer is D.

12) The function of the parallel line can be found in terms of its slope and a given point by this formula:

y-y_{o} = m_{\parallel}\cdot (x-x_{o})

Where:

x_{o}, y_{o} - Components of the given point, dimensionless.

m_{\parallel} - Slope, dimensionless.

Its slope is the slope of the given, which must be transformed into its explicitive form:

-8\cdot x + 5\cdot y = 89

5\cdot y = 89 +8\cdot x

y = \frac{89}{5}+\frac{8}{5} \cdot x

The slope of the parallel line is \frac{8}{5}.

If x_{o} = -8, y_{o} = 1 and m_{\parallel} = \frac{8}{5}, then:

y-1 = \frac{8}{5}\cdot [x-(-8)]

y-1 = \frac{8}{5}\cdot x +\frac{64}{5}

y = \frac{8}{5}\cdot x +\frac{69}{5}

The correct answer is B.

14) The function of the perpendicular line can be found in terms of its slope and a given point by this formula:

y-y_{o} = m_{\perp}\cdot (x-x_{o})

Where:

x_{o}, y_{o} - Components of the given point, dimensionless.

m_{\perp} - Slope, dimensionless.

Besides, a slope that is perpendicular to original line can be calculated by this expression:

m_{\perp} = -\frac{1}{m}

Where m is the slope of the original line, dimensionless.

The original slope is determined from the explicitive form of the given line:

-5\cdot x +9\cdot y = 49

9\cdot y = 49+5\cdot x

y = \frac{49}{9} +\frac{5}{9}\cdot x

The original slope is \frac{5}{9}, and the slope of the perpendicular line is:

m_{\perp} = -\frac{1}{m}

m_{\perp} = -\frac{1}{\frac{5}{9} }

m_{\perp} = -\frac{9}{5}

If x_{o} = -8, y_{o} = 1 and m_{\perp} = -\frac{9}{5}, then:

y-1 = -\frac{9}{5}\cdot [x-(-8)]

y-1 = -\frac{9}{5}\cdot x-\frac{72}{5}

y = -\frac{9}{5}\cdot x -\frac{67}{5}

The correct answer is A.

7 0
3 years ago
Use the iterative rule to find the 11th term in the sequence.
dolphi86 [110]

Answer:

-4

Step-by-step explanation:

The general, nth term, of a sequence is given by the formula:

a_n=18-2n

We can plug in n = 1 to find the first term, thus we have:

a_1=18-2(1)\\a_1=16

We can plug in n = 2, to the find the 2nd term, which is:

a_2=18-2(2)\\a_2=14

Similarly, to get 11th term, we simply plug in n = 11 into the general term rule. so we have:

a_n=18-2n\\a_{11}=18-2(11)\\a_{11}=18-22\\a_{11}=-4

11th term is -4

3 0
3 years ago
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