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AysviL [449]
3 years ago
8

Find the Greatest Common Factor

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0
First one is 5, second one is 9, third one is 4.

Hope this helps. :)
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What is the estimate for 167
Kitty [74]

Answer:

170

Step-by-step explanation:

unless you are rounding to the hundred and it would be 200

4 0
3 years ago
What is the rate of change and initial value for the linear relation that includes the points shown in the table?
uysha [10]
X   1 2 3
y 10 8 6
So find the slope m:  (6-10)/(3-1) = -4/2 = -2
Going backwards when x = 0, y will be 12 (you can see this)
So
<span>Initial value: 12, rate of change: −2

</span>
4 0
3 years ago
4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr
Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single  bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = 3(4)^{5} =3072

ii) II bacteria P = 3(4)^{4} =768

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

3(4)^{10}- 3(4)^{8} =2949120

c) i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

i) P=3 (4)^{36/12}=192

The rate may not be constant for a longer time.  Hence this may not be accurate.

e) when splits into 2, we get

P=P_o (2^t) where P0 is initial and t = interval of time

7 0
3 years ago
The sum of two consecutive integers is 65. what are the two integers? show steps please.
Gnoma [55]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

\triangle~\fbox{\bf{KEY:}}

  • Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.

Let the first integer be x, and let the second integer be x+1.

Their sum is 65. Let's set up our equation:

\longmapsto\sf{x+x+1=65}

Combine like terms:

\longmapsto\sf{2x+1=65}

Subtract 1 from both sides of the equal sign:

\longmapsto\sf{2x=64}

Divide both sides by 2:

\longmapsto\sf{x=32}

To find the second integer, subtract the first integer from the sum of the two integers:

\longmapsto\pmb{65-32}

\longmapsto\pmb{33}

The integers are: 33 and 32.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

7 0
2 years ago
Type 500 words in 20 minutes<br><br><br> _______ words per minute
7nadin3 [17]

Answer:

25

Step-by-step explanation:

Divide 500/20

3 0
4 years ago
Read 2 more answers
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