2. Simplify A. B. C. D.

Why it is not possible for two lines to be parallel and perpendicular?

max2010maxim [7]

Parallel lines have the same slope. for example, the two lines y = 6x + 3 and
y = 6x - 5 are parallel because they have the same slope, 6x.

the slopes of perpendicular lines are opposite reciprocals, which means that you would flip the numbers of the fraction and make it negative. for example, the opposite reciprocal of -3x is 1/3x.

also, parallel lines never intersect, whereas perpendicular lines intersect at a 90 degree angle.

therefore, it isnt possible for two lines to be both parallel and perpendicular.

7 0

2 years ago

In ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45. What is the value of the cosine of ∠X to the nearest hundredth?

kotegsom [21]

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

Step-by-step explanation:

The given is,

In ΔWXY, ∠Y=90°

XW = 53

YX = 28

WY = 45

Step:1

Ref the attachment,

Given triangle XWY is right angled triangle.

Trigonometric ratio's,

$Cos$ ∅ $= \frac{Adj}{Hyp}$

For the given attachment, the trigonometric ratio becomes,

$Cos$ ∅ $= \frac{XY}{XW}$ .....................................(1)

Let, ∠X = ∅

Where, XY = 28

XW = 53

Equation (1) becomes,

$Cos$ ∅ $= \frac{28}{53}$

$Cos$ ∅ = 0.5283

∅ = $cos^{-1}$ (0.5283)

∅ = 58.109°

Result:

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

4 0

2 years ago

HURRRYYYYYY Solve for t. 4/3 = t/7

VladimirAG [237]

Answer:

Step-by-step explanation:

4/3 = t/7

Multiply by 7 on both sides

4/3 x 7 = t

28/3 = t

3 0

2 years ago

Read 2 more answers

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, wha

ohaa [14]

With replacement:

P(C,V)=(12/40)(28/40)

P(C,V)=336/1600

P(C,V)=21/100

3 0

3 years ago

Read 2 more answers

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

3 years ago