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3 years ago

PLEASE HELP ME!!! THANK YOU!!

Mathematics

1 answer:

vekshin13 years ago

7 0

Answer:

uuum

Step-by-step explanation:

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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

inn [45]

Answer:

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Step-by-step explanation:

The given expression is

$\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}$

First, we need to factor each denominator

$\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}$

So, the least common factor (LCF) is $x(x-3)(x+3)$ , because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

$\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}$

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Therefore, the expression is equivalent to

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

8 0

3 years ago

Read 2 more answers

Which ist shows all the factors of 36?

____ [38]

Answer:

the first one

1, 2, 3, 4, 6, 9, 12, 18, 36

5 0

3 years ago

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A race car can complete 8 laps in 1/3 hour. At this rate, how many hours will it take the race car to complete 1 lap? 1/240 1/24

Marrrta [24]

Answer:

Step-by-step explanation:

The race car is doing 8 laps in 1/3 hour, in one hour the car is doing:

8laps * (1/3) hour) = 8*3 laps / 1hour = 24 laps/hour.

Now, to complete one lap, the car will it take:

1 lap * (1 hour / 24 laps) = 1/24 hours the race car requires to complete 1 lap. Right answer is:

8 0

3 years ago

What is the factored form of c^2=5c

mestny [16]

$c^2=5x\\
c^2-5c=0\\
c(c-5)=0
$

4 0

3 years ago

Define a sequence by a1=3 and an=3an−1. Find the first four terms of the sequence. Give a simplified integer answer.

aalyn [17]

Answer:

The first four terms are 3,9,27,81

Step-by-step explanation:

Given first term of sequence is $a_{1} = 3$

Given 'n' t h term is $a_{n} = 3 a_{n-1}$ .............(1)

here we put n = 2 in equation (1)

$a_{2} = 3a_{2-1}$

$a_{2} = 3 a_{1}$ ..............2

put $a_{1} = 3$ in equation (2)

$a_{2} = 3(3)$

$a_{2} = 9$

put n=3 in equation (1)

$a_{3} = 3 a_{3-1}$

$a_{3} = 3a_{2}$

$a_{3} = 3 (9) = 27$

put n= 4 in equation (1)

$a_{4} = 3 a_{4-1}$

$a_{4} = 3 a_{3}$

$a_{4} = 3(27) = 81$

The first four terms of the sequence is

3 , 9, 27 , 81 ....this is geometric sequence

a =3 and ratio term is r =3

6 0

3 years ago