Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:
Step-by-step explanation:
4/18×2/92
=1/9×1/23
=1/207
1/9×3/63
=1/3×1/23
=1/69
12/14×1/84
=1/14×1/7
=1/98
1/7×5/65
=1/7×1/13
=1/91
17/20×1/61
=17/1220
4 1/4 ×3 1/22
=17/4×67/22
=1,139/88
=12 83/88
3 5/6×4 1/23
=23/6×93/23
=93/6
=15 3/6
=15 1/2
2 1/2×4 7/84
=5/2×343/84
=1715/168
=10 35/168
I have answered more than 2 from each set
Answer: 1¹/₈ hours
Step-by-step explanation:
Joelle spent 1¹/₂ hours reading and Rileigh spent 3/4 of that time.
To find out how much time Rileigh spent, multiply the fractions but first convert the improper fraction to a proper fraction:
= 1¹/₂ = 3/2
= 3/2 * 3/4
= 9/8
= 1¹/₈ hours
