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aliina [53]
3 years ago
10

If f and g are inverse functions, what is (fog)(-1)

Mathematics
1 answer:
Tamiku [17]3 years ago
3 0
Fog is the answer ur welcome
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I need help with the bottom question
Sati [7]

Answer:

Step-by-step explanation:

they want to know  a point on the line... that has a gradient ( think slope )  of -1/3  and has the point of (-2,5)  on it. So find the formula for that line

with the point slope formula  y-y1 = m(x - x1)

plug in what we know

y - 5 = - 1/3 (x -(-2))

y - 5 = -1/3(x+2)

y - 5 = -1/3x - 2/3

y = - 1/3x - 2/3 + 5

y = - 1/3x + 4 1/3

y = -1/3x + 13 / 3

Now use your formula to find any new point plug in 1 for x ( b/c it's easy)

y = 12/3   when x= 1.  so ( 1, 4 )  is another point on the line  :)

don't forget to show your work  :P

5 0
3 years ago
4.3x - 6 = 8 + 2.3x*
Akimi4 [234]

Answer:

x = 7

Step-by-step explanation:

Follow the following steps

4.3x - 6 = 2.3x + 8 \\  - 2.3x \:  \: \:  \:  \:  \:  \:  \:   \:  - 2.3x \\ 2x - 6 = 8 \\  + 6  \:  \:  \:  \:  + 6 \\ 2x = 14 \\  \div 2 \:  \:  \div 2 \\ x = 7

7 0
3 years ago
Matthew was modeling an activity to the class. In a brown paper bag, he had 3 red marbles, 2 blue, and 5 green marbles. What is
luda_lava [24]
Probability of getting a red marble: 3/10
probability of getting a blue marble (after removing a red marble): 2/9

multiply the two fractions together:
6/90

simplify (divide by 6): 1/15 or .06666 repeating
4 0
3 years ago
What is the degree 3 polynomial that has zeros -3,2 and 5 and in which the coefficient of x^2 is -8?
Setler [38]
For zeroes/roots r1,r2, r3
the facors of the polynomial is
(x-r1)(x-r2)(x-r3)

roots
-3,2,5
(x-(-3))(x-2)(x-5)
(x+3)(x-2)(x-5)
the coefient of the x term is -4
so mutliply the whole thing by 2

(2)(x+3)(x-2)(x-5)

expand
f(x)=2x^3-8x^2-22x+60
3 0
4 years ago
If you are dealt 6 cards from a shuffled deck of 52​ cards, find the probability of getting four queens and two kings.
kicyunya [14]

Answer:

The probability is 0.000000207176

Step-by-step explanation:

In this question, we are asked to calculate the probability that if 6 cards are selected from a deck of cards, we will be having 4 kings and 2 queens.

Before we answer, we should understand that in a deck of cards, there are 4 queens and 4 kings. The probability of selecting a king is the same as the probability of selecting a queen which is 4/52 = 1/13

Okay now we want to find the probability of the six cards being 4 kings and 2 queens. Since the probabilities are equal, we proceed to calculate at the same time.

That would be (1/13)^6 = 0.000000207176

The probability of selecting 4 kings and 2 queens is 0.000000207176

6 0
4 years ago
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