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ExtremeBDS [4]
3 years ago
8

How do you solve this problem?

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0

Answer:

x=48

Step-by-step explanation:

x-3              15

------------ = ----------

6                      2

We can use cross products to solve this problem

(x-3) *2 = 6*15

Distribute

2x-6 = 90

Add 6 to each side

2x-6+6 = 90+6

2x=96

Divide by 2

2x/2 = 96/2

x = 48

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Elenna [48]

Answer:

True ( A )

Step-by-step explanation:

4 ( 5 ) - 2 =  2 ( 5 ) + 8

20 - 2 = 10 + 8

18 = 18

This is a correct statement because 18 does equal 18

5 0
3 years ago
Read 2 more answers
Given f(x) = 5x + 7,g(x) = 3x-1 find f(g(x))
kakasveta [241]

Answer:

f(g(x)) = 15x + 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Distributive Property

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Composite Functions

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 5x + 7

g(x) = 3x - 1

<u>Step 2: Find</u>

  1. Substitute in functions:                                                                                    f(g(x)) = 5(3x - 1) + 7
  2. [Distributive Property] Distribute 5:                                                                 f(g(x)) = 15x - 5 + 7
  3. [Addition] Combine like terms:                                                                        f(g(x)) = 15x + 2
7 0
3 years ago
Use the quadratic formula to solve for the roots of the following equation.<br> x 2 – 4x + 13 = 0
Artyom0805 [142]
  • Quadratic Formula: x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} , with a = x^2 coefficient, b = x coefficient, and c = constant

With our equation, plug in the values:

x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}

Next, solve the exponent and multiplications:

x=\frac{4\pm \sqrt{16-52}}{2}

Next, solve the subtraction:

x=\frac{4\pm \sqrt{-36}}{2}

Next, factor out i (i = √-1):

x=\frac{4\pm \sqrt{36}i}{2}

Next, solve the square root:

x=\frac{4\pm 6i}{2}

Lastly, divide and <u>your answer is:</u>

x=2\pm 3i

5 0
3 years ago
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PLEASEEE I NEED HELPPP!!!!
taurus [48]

Answer:

#carry on learning

mark me as brainliest

Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)

I really need this question answered

By:

I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).

I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.

The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:

y = 6x + b

We need to find b, so substitute the point (-5,4) that we know is on the line:

4 = 6*(-5) + b and solve for b

4 = -30 + b

b = 34

The line is y = 6x + 34

4 0
2 years ago
2. Is the expression 2 • 4' equal to the expression 8"? Explain your answer.
liberstina [14]
Yes, this is because 2*4 equals 8
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2 years ago
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