Answer:
A=152
K= -Ln(0.5)/14
Step-by-step explanation:
You can obtain two equations with the given information:
T(14 minutes) = 114◦C
T(28 minutes)=152◦C
Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:
Applying the following property of exponentials numbers in (II):
Therefore 
can be written as 
Replacing (I) in the previous equation:
Solving for k:
Subtracting 190 both sides, dividing by -76:
Applying the base e logarithm both sides:
Ln(0.5)= -14k
Dividing by -14:
k= -Ln(0.5)/14
Replacing k in (I) and solving for A:
Dividing by 0.5
A=152
Answer:
First, calculate 18% of 23.
23 x 0.18 = 4.14
Then, add this value (the increase) to the original value of 23.
23 + 4.14 = 27.14
Rounding off, we get 27.
Step-by-step explanation:
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the true population mean textbook weight.
Number of sample, n = 22
Mean, u = 64 ounces
Standard deviation, s = 5.1 ounces
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
64 ± 1.645 × 5.1/√22
= 64 ± 1.645 × 1.087
= 64 ± 1.788
The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces
The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces
Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces
Answer:
420 (lol)
Step-by-step explanation:
Answer:
8 degrees Fahrenheit
Step-by-step explanation:
