Table:
x y
-3 0.5
-2 1
-1 2.5
0 5
1 8.5
Now, y = ax^2 + bx + c
Start replacing x = 0 and y = 5
5 = a(0) + b(0) + c => c = 5.
Now, replace any other two pair of data:
(-2, 1) => -1 = a(-2)^2 + b(-2)
-1 = 4a - 2b
(1, 8.5) => 8.5 = a(1)^2 + b(1)
8.5 = a + b
Solve the system
4a - 2b = - 1
a + b = 8.5
=>
4a - 2b = - 1
2a + 2b = 17
-------------------------
6a = 16
=> a = 16 / 6 = 8/3
b = 8.5 - a = 17/2 - 8/3 = 35/6
=> y = (8/3)x^2 + (35/6)x + 5 <--------- answer
Answer:
Weight of dog: 34 pounds,
Weight of cat: 12 pounds.
Step-by-step explanation:
Let d represent weight of dog and c represent weight of cat.
We have been given that a dog weighs two pounds less than three times the weight of a cat.
3 times weight of cat: 
We can represent the given information in an equation as:

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

Equate both equations:






Therefore, the weight of cat is 12 pounds.
Substitute
in equation (2)



Therefore, the weight of dog is 34 pounds.
Answer:
I believe it is 11.48 I am so so sorry if its wrong
Step-by-step explanation:
.93 * 24 = 22.32
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X=-6
You plus in x as -6 and you already know that y=5x and you plug in x=-6
It should look like 2(-6)-5(-6)=18