Given:

To find:
The f'(y).
Solution:
Chain rule of differentiation:
![[f(g(x))]'=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Bf%28g%28x%29%29%5D%27%3Df%27%28g%28x%29%29g%27%28x%29)
Differentiation of exponential:

We have,

Differentiate with respect to y.



Therefore, the differentiation of the given function is
.
Answer:
I could help you, but first-
are you missing an number at the end of "3x+7y=" ?
Answer:
In vertex form the equation is 
In standard form the equation is 
Step-by-step explanation:
The equation of the directrix tells us that this is an x-squared parabola. Because the directrix is above the vertex, the parabola will open downward. The vertex form of this equation is:

where p is the number of units between the directrix and the vertex. The number of units here is .5 or 1/2. Filling in the coordinates of the vertex and the p value of 1/2:

Simplifying we have:

Divide both sides by 2 to get:

Add 2 to both sides to get the final vertex form:

If you want that in standard form, you first need to expand the squared term to get:

Order of operations tells us that we have to distribute in the -1/2 first to get:

which simplifies to the standard form:
