Answer:
<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>
By De morgan's law

which is Bonferroni’s inequality
<h3>Result 1: P (Ac) = 1 − P(A)</h3>
Proof
If S is universal set then

<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>
Proof:
If S is a universal set then:

Which show A∪B can be expressed as union of two disjoint sets.
If A and (B∩Ac) are two disjoint sets then
B can be expressed as:

If B is intersection of two disjoint sets then

Then (1) becomes

<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>
Proof:
If A and B are two disjoint sets then

<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>
Proof:
If B is subset of A then all elements of B lie in A so A ∩ B =B
where A and A ∩ Bc are disjoint.

From axiom P(E)≥0

Therefore,
P(A)≥P(B)
Answer:
5(2 + y)
Step-by-step explanation:
The sum of 2 and y is 2 + y and 5 times this sum is
5(2 + y)
What form do you need it in?
Answer:
17
Step-by-step explanation:
We have two congruent triangles here. Thus, b must be 17.
To calculate mean: Just add up all the numbers, then divide by how many numbers there are.345 + 673 + 728 +775 + 822 +827 +839 + 951 = 5960/8 = 745
633 + 673 + 728 +775 + 822 +827 +839 + 951 = 6248/8 = 781781- 745 = 35 It increases by 35To find the Median, place the numbers in value order and find the middle. BUT, with an even amount of numbers things are slightly different. In that case we find the middle pair of numbers, and then find the value that is half way between them. This is easily done by adding them together and dividing by two. 345 673 728 775 822 827 839 951 The median = 822-775 /2
The median =23.5After the change633 673 728 775 822 827 839 951 The median = 822-775 /2
The median =23.5The median stays the same.