3 years ago

How do you solve 8-4(3-5)^2

Mathematics

2 answers:

Ganezh [65]3 years ago

3 0

Answer:

-8

Step-by-step explanation:

8-4(3-5)^2

8-4(-2)^2

8-4x4

8-16

-8

jolli1 [7]3 years ago

3 0

Answer: answer is -8

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3 years ago

Matt is running in a 9 mile race over

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Step-by-step explanation:

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3 years ago

In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

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2 years ago

What is the product of 2x(5+3)-4^2

Zigmanuir [339]

Answer:

2×8-4^2

=16-16

0 is the porduct

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2 years ago