The deer population of a certain area is modeled by the formula: P=578e^0.045t where t is measured in years. In approximately ho
1 answer:
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Answer:
So for the first spinner, the probability of the arrow pointing to blue on a spin is 1/4, the probability of it pointing to green is 1/4 and so on. This assumes that each section is the same physical size.
Step-by-step explanation:
Answer:
Width of intervals: 8
Step-by-step explanation:
We first look at how data is represented in a stem-leaf diagram.
Any number of the left (before -) is the stem and all numbers on right (after -) are the leaves. Each combination of stem and leaf represents one number. For example: 1 - 332 represents: 13, 13, 12.
Our data is as follows:
13, 13, 12, 24, 25, 31, 31, 35, 37, 42, 43, 41, 52, 51, 51, 52
To calculate the width of the frequency distribution chart, we have the following formula:
The range of any data set = Maximum value in the data set - Minimum value in the data set
Maximum value in this case as seen from the data is 52 and minimum is 12.
Range = 52 - 12 = 40
Since we had only 5 stems in the data, we shall use that as the number of classes required in the frequency distribution chart.
Hence, the class width in this data set will be 8.
To make the intervals, we begin from the minimum value and add 8 to it. The intervals will be:
12 - 20
20 - 28
28 - 36
36 - 44
44 - 52
Observe, that all the values of the stem lie within each interval.
For example, there are 3 values for stem 1: 12, 13, 13 and each lie in the first interval 12 - 20.
Next, the values of stem 2 are 24 and 25. Each of these value lie in the second interval 20 - 28; and henceforth.
Answer:
Let the distance between woman and pole be "x".
From diagram,
In ΔOAB,
tan 18 =
tan 18 =
∴ x = ................ (1)
In ΔOBC
tan 14 =
tan 14 =
y = x × tan 14 ..............(2)
equating (2) in (1), we get;
x =
x =
∵ tan 18 + tan 14 = 0.574
<em>∴ x = 113.2 ft</em>
<em>i.e. The her distance from the pole is 113.2 ft.</em>
