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Tanya [424]
2 years ago
11

Please help me i don't know what else to put here.........................

Mathematics
1 answer:
Pepsi [2]2 years ago
3 0
ANSWERRR
1. 15%
2.20%
3.45%
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What is 0.0008235 in scientific notation
larisa [96]
I think this is the Answer

8.235*10^-4

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3 years ago
HELP
lbvjy [14]
Y=9r, r=r

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Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0
natita [175]

Answer:

\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

Step-by-step explanation:

Given differential equation,

(x^2 + y^2) dx + (x^2 - xy) dy = 0

\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)

Let y = vx

Differentiating with respect to x,

\frac{dy}{dx}=v+x\frac{dv}{dx}

From equation (1),

v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}

v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}

v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}

v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}

x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v

x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}

x\frac{dv}{dx}=\frac{v+1}{v-1}

\frac{v-1}{v+1}dv=\frac{1}{x}dx

Integrating both sides,

\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx

\int{\frac{v-1+1-1}{v+1}}dv=lnx + C

\int{1-\frac{2}{v+1}}dv=lnx + C

v-2ln(v+1)=lnx+C

Now, y = vx ⇒ v = y/x

\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

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3 years ago
If you have 30 spoons, according to the table below, how many forks will you have?
Marysya12 [62]

\bf \begin{array}{|c|ll|} \cline{1-3} Forks&16&\stackrel{\downarrow }{8}\\ Spoons&10&\underset{\uparrow }{30}\\ \cline{1-3} \end{array}

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3 years ago
Which is the correct answer and pls explain why
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I think n2+2
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