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The first picture represents the elements in B that are not (also) in A. So, we want the set difference of B and A:
For the second picture, we can work like this: if we take all the elements belonging to A, we only need to add the bottom-right part, which is the intersection of B and C. So, we can express the blue part as
When light moves from one medium to another, it is refracted. If it moves from a medium with refractive index n1 to one with refractive index n2, with an incidence angle to the surface normal of θ1, the refraction angle θ2 can be calculated from Snell's law.
The Snell's law states that the ratio of the sines of the angles of incidence and refraction of a wave (in this case beam/light) are constant when it passes between two given media.
Given that a <span>laser travels from glass to water at an angle of 35° with the normal, </span>
<span>. If water has an index of refraction of 1.33 and glass has an index of refraction of 1.52, then we have:
</span>
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The Snell's law states that the ratio of the sines of the angles of incidence and refraction of a wave (in this case beam/light) are constant when it passes between two given media.
Given that a <span>laser travels from glass to water at an angle of 35° with the normal, </span>
</span>
</span>