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Rama09 [41]
4 years ago
12

What is 11:40 - 1 1/2

Mathematics
1 answer:
suter [353]4 years ago
3 0

Answer: 10:10

Step-by-step explanation:

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What are the equations of the asymptotes of the graph of f(x)=(5/x+7)−8 ?
ludmilkaskok [199]

Answer:

\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1

The graph of the function is also attached.

Step-by-step explanation:

Considering the expression

\:f\left(x\right)=\left(\frac{5}{x}+7\right)-8\:\:

\mathrm{Simplify}\:\frac{5}{x}+7-8:\quad \frac{5}{x}-1

\mathrm{Vertical\:asymptotes\:of\:}\frac{5}{x}-1:

Go over every undefined point x = a and check if at least one of the following statement is true.

\lim _{x\to a^-}f\left(x\right)=\pm \infty

\lim _{x\to a^+}f\left(x\right)=\pm \infty

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{5}{x}-1\mathrm{\:and\:compare\:to\:zero}

x=0

The following points are undefined

x=0

\mathrm{The\:vertical\:asymptotes\:are:}

x=0

\mathrm{Horizontal\:Asymptotes\:of\:}\frac{5}{x}-1:

\mathrm{Check\:if\:at\:}x\to \pm \infty \mathrm{\:the\:function\:}y=\frac{5}{x}-1\mathrm{\:behaves\:as\:a\:line,\:}y=mx+b

\mathrm{Find\:an\:asymptote\:for\:}x\to -\infty \::

\lim _{x\to -\infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to -\infty \:}\frac{\frac{5}{x}-1}{x}=0

\lim _{x\to -\infty \:}f\left(x\right)-mx=\lim _{x\to -\infty \:}\frac{5}{x}-1-0x=-1

y=-1

\mathrm{Find\:an\:asymptote\:for\:}x\to \infty:

\lim _{x\to \infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to \infty \:}\frac{\frac{5}{x}-1}{x}=0

\lim _{x\to \infty \:}f\left(x\right)-mx=\lim _{x\to \infty \:}\frac{5}{x}-1-0x=-1

y=-1

\mathrm{The\:horizontal\:asymptote\:is:}

y=-1

Therefore,

\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1

The graph of the function is also attached.

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16x -7&lt;-71<br><br><br> Please Help
saw5 [17]

Answer:

x<-4

Step-by-step explanation:

16x  - 7 <  - 71 \\ 16x <  - 71  + 7 \\ 16x <  - 64 \\ x <  - 4

4 0
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