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RoseWind [281]
3 years ago
7

Help me solve this please

Mathematics
1 answer:
shutvik [7]3 years ago
7 0

Answer:

D'G' = 52.5 units

Step-by-step explanation:

Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5

D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )

G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )

Calculate D'G' using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)

D'G' = \sqrt{(-28-3.5)^2+(-17.5-24.5)^2}

       = \sqrt{(-31.5)^2+42^2}

       = \sqrt{992.25+1764}

        = \sqrt{2756.25}

         = 52.5 units

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PLEASE HELP ASAP!!
Anon25 [30]

Answer:

16 inches, and 10 inches tall, aka Answer D.

So because, they are asking the largest image for the photograph,

so 8 * 2 = 16

and 10 * 2 = 20 but 20 can't go into 12.

Step-by-step explanation:

I think this is right sry if its not

3 0
3 years ago
Read 2 more answers
A countertop is 11 feet long and 4 fee t wide.
zloy xaker [14]

Answer:

4.09m^2

Step-by-step explanation:

A countertop is 11 feet long and 4 fee t wide.

Using the conversion

1foot = 0.305 meter

11fet = 11(0.305)

11feet = 3.355 m

4 feet= 4 * 0.305

4feet = 1.22m

Area of the countertop = Length * Width

Area of the countertop = 3.355 * 1.22

Area of the countertop = 4.0931m^2

Hence the required area is 4.09m^2 to 2 decimal places

7 0
3 years ago
You can buy 5 stickers for $3. Write a proportion that gives the<br> cost c if you buy 12 stickers.
Reptile [31]

Answer:

$7.5

Step-by-step explanation:

Let

Quantity of stickers=x

Price of stickers=y

5 stickers cost $3

12 stickers cost $y

x/y = x/y

5/3 = 12/y

Cross product

5y=12*3

5y=36

Divide both sides by 5

5y/5 = 36/5

y=7.5

12 stickers= $7.5

Therefore, the price of 12 stickers= $7.5

5 0
3 years ago
What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?
german
For this case we have the following function:
 f(x) =  tan(\frac{x^2}{9})
 The average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2- x1}
 Evaluating the function for the given interval we have:
 For x = 1.25:
 f(1.25) = tan(\frac{1.25^2}{9})
 f(1.25) = 0.18
 For x = 2:
 f(2) = tan(\frac{2^2}{9})
 f(2) = 0.48
 Then, replacing values we have:
 AVR = \frac{0.48 - 0.18}{2 - 1.25}
 AVR = 0.4
 Answer:
 
the average value of on the closed interval [1.25, 2] is:
 
AVR = 0.4



3 0
3 years ago
Write an inequality for the graph. Then, in words, describe all the values of that make the inequality true.
kow [346]
-3 > x

The values that make this inequality true are those that are less than -3. The inequality does not include -3.
7 0
2 years ago
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