1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga_2 [115]
3 years ago
7

Identify the number soutions 5y^3-3y^2+8y=0

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

Answer: 0

Step-by-step explanation:

Step 1: factor left side of equation

y(5y^2-3y+8)=0

Step 2: set factors to equal zero

y=0 or 5y^2-3y+8=0

y=0

You might be interested in
Could some one help me please
solmaris [256]

Answer:

12

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to |a|≤5 ?
sladkih [1.3K]

Answer:

I think its  the first one but not 100 % sure

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Chris is calculating his deductions for his tax return. He is filing singly. He can claim $1,813 from property taxes, $1,513 fro
dimulka [17.4K]
You add
1,813 + 1,513 + 761 = 4,087
Then you subtract
5,700 - 4,087 = 1,613
It's C. The standard deduction is $1,613 better than Chris's deductions
I just took the test.
3 0
3 years ago
Read 2 more answers
20/8/15 plzzzzzz help
Nina [5.8K]

Answer:20/8/15= 0.16666666666

7 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
Other questions:
  • If you drive at 100km/hr for 6 hrs how far will you travel?
    15·2 answers
  • Find the area and round to the nearest hundredth
    15·1 answer
  • Can someone please answer this???? ASAP
    13·1 answer
  • What numbers satisfy A C
    8·1 answer
  • What is the solution to the equation -M+KX=J
    12·2 answers
  • Half of a sphere is stacked on top of a cone. They both share a circular base. The radius of the circle is 6 millimeters. The he
    6·2 answers
  • Two hot air balloons are traveling along the same path away from a town, beginning from different locations at the same time. He
    12·1 answer
  • NEED HELP ASAP WILL GIVE BRAINLY
    5·1 answer
  • A whole number is multiplied by six. What must the answer be?
    8·2 answers
  • Write the fraction as an 1/15 equivalent fraction with a denominator of 45.​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!