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anygoal [31]
3 years ago
6

Write down the temperature which is 5 degree below -2​

Mathematics
2 answers:
daser333 [38]3 years ago
6 0

Answer:

-7 degree

Step-by-step explanation:

Alchen [17]3 years ago
5 0

Answer:

-7

Step-by-step explanation:

-2 - 5 = -7

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Again with this please​
ElenaW [278]

Answer:

a) A dozen= 24

3 dozen= 24 x 3

= 72

b) 1 dozen= 12 bananas

A dozen cost= 24

So, 1 banana cost= 24/12

= 2

So, 6 bananas would be 2 x 6 = 12

c) 1 dozen= 12 bananas

A dozen cost= 24

1 banana cost= 24/12

= 2

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5 0
2 years ago
A triangular sail has a base length of 2.5 meters.The area of the sail is 3.75 square meters.How tall is the sail?
love history [14]
Area of a triangle = 1/2 x base x height

--------------------------------------
Find Height :
--------------------------------------
3.75  = 1/2 x 2.5 x height

3.75 = 1.25 x height 

height = 3.75 ÷ 1.25

height = 3 meters

----------------------------------------------------------------------------
Answer: The height is 3 meters.
----------------------------------------------------------------------------
7 0
3 years ago
3x squared - 2 x y when x=2 and y = 5
ira [324]

the Answer is 4 do order of operations

7 0
3 years ago
B. How many hours will Max have to work if he wants to earn $186?
velikii [3]
Is there anymore to the question?
8 0
3 years ago
Read 2 more answers
What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of
notsponge [240]

Answer:

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

Step-by-step explanation:

The question is as following:

The verticies of a triangle on the coordinate plane are

A(0, 0), B(2, 0) and C(0, 2).

What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?

=============================================

Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).

IF the triangle is dilated by a factor of k about the origin, then

(x,y) → (kx , ky)

that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

If a figure dilated by a factor of 1/3 about the origin

So, (x,y)\rightarrow (\frac{1}{3}x,\frac{1}{3}y)

<u>So, The coordinates of the triangle A'B'C' are:</u>

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

6 0
3 years ago
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