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anygoal [31]
3 years ago
6

Write down the temperature which is 5 degree below -2​

Mathematics
2 answers:
daser333 [38]3 years ago
6 0

Answer:

-7 degree

Step-by-step explanation:

Alchen [17]3 years ago
5 0

Answer:

-7

Step-by-step explanation:

-2 - 5 = -7

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Plalslslsllslslslslsps helpp
Nezavi [6.7K]

Answer:

1064 ft.

Step-by-step explanation:

Start by sketching out a figure to represent the situation, it should look something like this:

(See picture)

(Figure definitely not drawn to scale)

The angle marked in red measures 4.3°, then we can use the law of sines to solve for the height of the Eiffel Tower (represented as the variable x):

\frac{sin(4.3)}{80}= \frac{sin85.7}{x}\\x=\frac{80sin85.7}{sin4.3}\\x=1063.96592818...

Rounding gives 1064 ft.

7 0
2 years ago
How many inches are in 8.5 feet (show work please thank you you)
GalinKa [24]
8.5 feet(12 inches per foot)= 102 inches total
There are 102 inches in 8.5 feet
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3 years ago
HALLP QUICKKKK
Rina8888 [55]
To solve this we are going to use the formula for speed: S= \frac{d}{t}
where
S is the speed
d is the distance 
t is the time 

Let S_{l} be the speed of the boat in the lake, S_{a} the speed of the boat in the river, t_{l} the time of the boat in the lake, and t_{a} the time of the boat in the river. 

We know for our problem that <span>the current of the river is 2 km/hour, so the speed of the boat in the river will be the speed of the boat in the lake minus 2km/hour:
</span>S_{a}=S_{l}-2
We also know that in the lake the boat<span> sailed for 1 hour longer than it sailed in the river, so:
</span>t_{l}=t_{a}+1
<span>
Now, we can set up our equations.
Speed of the boat traveling in the river:
</span>S_{a}= \frac{6}{t_{a} }
But we know that S_{a}=S_{l}-2, so:
S_{l}-2= \frac{6}{t_{a} } equation (1)

Speed of the boat traveling in the lake:
S_{l}= \frac{15}{t_{l} }
But we know that t_{l}=t_{a}+1, so:
S_{l}= \frac{15}{t_{a}+1} equation (2)

Solving for t_{a} in equation (1):
S_{l}-2= \frac{6}{t_{a} }
t_{a}= \frac{6}{S_{l}-2} equation (3)

Solving for t_{a} in equation (2):
S_{l}= \frac{15}{t_{a}+1}
t_{a}+1= \frac{15}{S_{l}}
t_{a}=\frac{15}{S_{l}}-1
t_{a}= \frac{15-S_{l}}{S_{l}} equation (4)

Replacing equation (4) in equation (3):
t_{a}= \frac{6}{S_{l}-2}
\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}

Solving for S_{l}:
\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}
(15-S_{l})(S_{l}-2)=6S_{l}
15S_{l}-30-S_{l}^2+2S_{l}=6S_{l}
S_{l}^2-11S_{l}+30=0
(S_{l}-6)(S_{l}-5)=0
S_{l}=6 or S_{l}=5

We can conclude that the speed of the boat traveling in the lake was either 6 km/hour or 5 km/hour.
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4 years ago
15,000 times 3 fourths
Stells [14]

Answer:

11250

Step-by-step explanation:

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Step-by-step explanation:

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