Answer:
B. 1,900
Step-by-step explanation:
Answer:
loss
Step-by-step explanation:
you might want to check someone else answer first tho
Answer:
Step-by-step explanation:
band alone 11
choir alone 17
band and choir alone 4
band and math alone 7
math and choir alone 6
band choir and math 3
math alone 9 from 11+4+10+6+17 + M = 57
so
2 classes = 4+7+6 = 17
17 students take exactly two classes with Mr. Green
Let X be a discrete random variable with geometric distribution.
Let x be the number of tests and p the probability of success in each trial, then the probability distribution is:
P (X = x) = p * (1-p) ^ (x-1). With x = (1, 2, 3 ... n).
This function measures the probability P of obtaining the first success at the x attempt.
We need to know the probability of obtaining the first success at the third trial.
Where a success is defined as a customer buying online.
The probability of success in each trial is p = 0.3.
So:
P (X = 3) = 0.3 * (1-0.3) ^ (3-1)
P (X = 3) = 0.147
The probability of obtaining the first success at the third trial is 14.7%
N=d-2
q=n+d =>q=(d-2)=q=2d-2
25q+5n+10d=525
replace q and n with d
25(2d-2) +5(d-2)+10d=525
50d-50+5d-10+10d=525
65d=585
d=9
n=7
q=16
