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3 years ago

Is this relationship a function?

Mathematics

1 answer:

Oduvanchick [21]3 years ago

6 0

Answer:

No, this is not a function.

Step-by-step explanation:

*Domain - {0,1,3,5}

*Range - {2,5,2,4.8}

Rule: A function is a special type of relation in which each value of the domain is paired with exactly one value of the range.

Since 0 pairs with both 2 and 5, this would not be a function.

Hope this helps!

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Explain in your own words why (x + y)2 ≠ x2 + y2. Provide a numerical example to illustrate.

bekas [8.4K]

Im not sure if you wrote this wrong because (x+y)2 does equal x2+y2. An example would be if x equals 3 and y equals 4 (3+4)2=(3)2+(4)2 (7)2=6+8 14=14.

6 0

3 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

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3 years ago

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ki77a [65]

Answer:

The area of this triangle is.. $30 in^2$

Step-by-step explanation:

6 x 10 divided by 2 = 30

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3 years ago

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2 years ago

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4a + c =17 A B C are consecutive numbers.

iris [78.8K]

A=3
B=4
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