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Misha Larkins [42]
3 years ago
9

Is this relationship a function?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
6 0

Answer:

No, this is not a function.

Step-by-step explanation:

*Domain - {0,1,3,5}

*Range - {2,5,2,4.8}

Rule:  <em>A function is a special type of relation in which each value of the </em><em>domain is paired with </em><u><em>exactly one value</em></u><em> of the range.</em>

Since 0 pairs with both 2 and 5, this would not be a function.

Hope this helps!

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HELP ASSAP WILL MARK BRAINIEST!!!!
lesantik [10]

Answer:

The cost of each pound of jelly beans: $2.75

The cost of each pound of almonds: $3.75

Step-by-step explanation:

A = The cost of each pound of almonds

J = The cost of each pound of jelly beans

9A + 7J = 53

3A + 5J = 25

Multiply 3A + 5J = 25 by (-3)

-9A  -15J = -75

Now 2 new equations:

9A + 7J = 53

-9A  -15J = -75

------------------------------Add

-8J = - 22

J = 2.75

3A + 5(2.75)= 25

3A + 13.75 = 25

3A = 11.25

A = 3.75

6 0
3 years ago
Determine whether the graph of each pair of equations are parrallel, perpendicular, or neither
Luba_88 [7]

Answer: 1: parrallel

2:perpendicular

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Step-by-step explanation:

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3 years ago
Which expression is equivalent to 4f/3÷1/4f​
charle [14.2K]

Answer:

\large\boxed{\dfrac{4f}{3}\div\dfrac{1}{4f}=\dfrac{16f^2}{3}}

Step-by-step explanation:

\dfrac{4f}{3}\div\dfrac{1}{4f}=\dfrac{4f}{3}\cdot\dfrac{4f}{1}=\dfrac{(4f)(4f)}{(3)(1)}=\dfrac{16f^2}{3}

6 0
3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs.
Aliun [14]

Answer:

i think its 24

Step-by-step explanation:

2=2

8 0
3 years ago
9.45×10^6 in standard form
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Answer:

That is written in standard form, no changes are needed.

9.45×10^6 is the answer

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