Question

6. (07.02 MC)

Answer 1

Given:

A right angled triangle in the figure.

To find:

The value of x.

Solution:

We know that, in a right angled triangle,

$\tan \theta =\dfrac{Opposite}{Adjacent}$

For the given triangle,

$\tan (x^\circ) =\dfrac{8}{15}$

$x^\circ =\tan^{-1} \dfrac{8}{15}$

$x^\circ =28.072487^\circ$

$x^\circ \approx 28.07^\circ$

Therefore, the value of angle x is 28.07°.