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Solution:
Let each pond of jelly beans cost $x.
and each pond of almonds cost $y.
Then we can write
![6x+2y=12.......(i)](https://tex.z-dn.net/?f=6x%2B2y%3D12.......%28i%29)
![3x+5y=15.....(ii)](https://tex.z-dn.net/?f=3x%2B5y%3D15.....%28ii%29)
Now solve these two equations together using substitution we get
![3x=15-5y](https://tex.z-dn.net/?f=3x%3D15-5y)
![30-10y+2y=12\\ \\ -8y=12-30\\ \\ -8y=-18\\ \\ y=2.25\\ \\ 3x=15-5y=15-5*2.25=3.75\\ \\ x=1.25](https://tex.z-dn.net/?f=30-10y%2B2y%3D12%5C%5C%0A%5C%5C%0A-8y%3D12-30%5C%5C%0A%5C%5C%0A-8y%3D-18%5C%5C%0A%5C%5C%0Ay%3D2.25%5C%5C%0A%5C%5C%0A3x%3D15-5y%3D15-5%2A2.25%3D3.75%5C%5C%0A%5C%5C%0Ax%3D1.25)
Hence each pond of jelly bean cost 1.25$
Each pond of almond costs 2.25$
Brother one: x
Brother two: x + 15
---
Make them add up to 55 in an equation.
x + (x + 15) = 55
Combine like terms.
2x + 15 = 55
Subtract 15 from both sides.
2x = 40
Divide both sides by 2.
x = 20
Plug 20 for x into brother two.
(20) + 15 = 35
Brother one has saved $20, brother two has saved $35.
I am not sure if this is right , but I tried . I hope I helped !