Select Is a Function or Is not a Function to correctly classify each relation.
<span><span>Title Is a Function Is not a Function</span><span><span><span><span>{<span><span>(<span>3, 7</span>)</span>,<span>(<span>3, 6</span>)</span>,<span>(<span>5, 4</span>)</span>,<span>(<span>4, 7</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>1, 5</span>)</span>,<span>(<span>3, 5</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>6, 4</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>2, 3</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>5, 8</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>0, 4</span>)</span>,<span>(<span>3, 2</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>6, 5</span>)</span></span>}</span></span>
</span></span></span>
If you look closely at the options, the first 3 options will not produce an image that will be in Quadrant II with the vertices coinciding HGFE.
But if you look at the 4th option, translating the points 8 units to the left will produce an image in Quadrant III. Reflecting the image across the x-axis will produce triangle HGFE.
The answer is 96 F,O, >,< or = 13 C. Hop this helps.
Answer:
and 
Step-by-step explanation:
Given
See attachment
Required
Identify the vertical angles
Keynotes
- Vertical angles opposite one another
- Vertical angles are equal to one another
Using the keynote as a reference, we have the following observation from the attachment:
and are opposite
and are congruent
Hence:
and are vertical
<em>(d) is correct</em>
Answer:
(1)
Multiplying by 3 both sides of the equality you get that
3u is in the Span of the vectors 
.
(2)
That's not true, consider the following counter example.
is a linear combination of 
but is NOT a linear combination of 
Step-by-step explanation:
(1)
As the hint indicates, you know that
Then, if you multiply both sides of the equality by 3, you get that
And that's it. 3u is in the Span of the vectors
(2)
That's not true, consider the following counter example.
is a linear combination of but is NOT a linear combination of
