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2 years ago

Which statements are true? Select all that apply.

Mathematics

2 answers:

galina1969 [7]2 years ago

7 0

Your going to have to give us more information then that

Reika [66]2 years ago

5 0

I need more information then that in order to answer it-

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X is 13 less than 17. WRITE AN EQUATION TO REPRESENT THE statement.

vovikov84 [41]

Answer:

X=4

Step-by-step explanation:

13 less than 17 would be 4 becayse if you do 17-13=4

6 0

3 years ago

Tyler's family is using a shipping trailer that is 5 feet tall 4 feet wide and 12 feet long to load boxes of apples in each box

NikAS [45]

the volume would be 18in x 24in x 12in.

5 0

3 years ago

Can I have to answers for all the ones that are circled please :D

kipiarov [429]

32. Answer: 2+5×3=17
33. Answer: 2×5+3=17
34. Answer: 2×5×3=30
35. Answer: 2×5-3=7

3 0

3 years ago

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

2 years ago

"In the 45°-45°-90° triangle above, r = 10. Find the other two lengths.

Basile [38]

We are given a right triangle that has angles of 45°-45°-90°. This would indicate that the triangle is an isosceles type. We can use some trigonemetric functions to solve for the other legs. We do as follows:

sin 45 = p / 10

p = 5√2

cos 45 = q /10

q = 5√2

<span>Hope this answers the question. Have a nice day.</span>

5 0

3 years ago