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3 years ago

13

Andy deposits $100 in a bank account that earns $5 interest annually. Write an equation for the balance, p, in the account after

y years.

1 answer:

Lana71 [14]3 years ago

7 0

Answer:

y5+100=p

Step-by-step explanation:

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4. Use the graph for the following:<br><br> Please answer<br> Picture is included

sergiy2304 [10]

Answer:

(a) 9

(b) -2

Step-by-step explanation:

it is very important to start by finding the equation of the line then substitute in some values.

6 0

1 year ago

In the diagram below, GH is parallel to DE . If GH is 3 more than EH FH=10, and DE=12 find the length of EH. Figures are not nec

steposvetlana [31]

Answer: 5

Step-by-step explanation:

Since $\overline{GH} \parallel \overline{DE}$ , by the corresponding angles theorem, $\angle FGH \cong \angle FDE, \angle FHG \cong \angle FED$ . This means $\triangle FGH \sim \triangle FDE$ by AA.

As corresponding sides of similar triangles are proportional,

$\frac{10}{x+3}=\frac{10+x}{12}\\(10)(12)=(10+x)(x+3)\\120=x^{2}+13x+30\\x^{2}+13x-90=0\\(x+18)(x-5)=0\\x=-18, 5$
However, as distance must be positive, we consider the positive solution, x=5.

Therefore, the answer is <u>5</u>

6 0

2 years ago

What is PA <br> Enter your answer in the box

SSSSS [86.1K]

Answer:

3

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : $PK^{2}=PE^{2}+KE^{2}$

⇒ $PE^{2}=PK^{2}-KE^{2}$

⇒ $PE=\sqrt{PK^{2}-KE^{2} }$

⇒ $PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }$

⇒ $PE=3$

Therefore, $PA=3$

3 0

3 years ago

Liam opened a savings account with a $400 deposit and a simple interest rate of 7.5%. If the balance of the account is now $670

Vinil7 [7]

Answer:

If he deposited weekly, he would be depositing 9 dollars each week.

Step-by-step explanation:

Just thank me later and click the crown at the top of this answer if it helped ;)

6 0

3 years ago

Five times the sum of a number and 27 is greater than or equal to six times the sum of that num

stepladder [879]

Question:

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.

What is the solution set of this problem?

Answer:

$x \leq -21$

Step-by-step explanation:

Given

<em>Represent the number with x</em>

So:

$5 * (x + 27) \geq 6 * (x + 26)$

Required

Determine the solution set

$5 * (x + 27) \geq 6 * (x + 26)$

Open Both Brackets

$5 * x + 5 * 27 \geq 6 *x + 6 * 26$

$5x + 135 \geq 6x + 156$

Collect Like Terms

$5x - 6x \geq 156-135$

$- x \geq 21$

Multiply both sides by -1

$x \leq -21$

Hence, the solution set is $x \leq -21$

7 0

3 years ago