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zhuklara [117]
3 years ago
14

If prizes for a Carnival are priced at 5 for 80 cents how much wood to 50 prizes cost

Mathematics
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

$8

Step-by-step explanation:

If 5 prizes cost 80 cents that means that 1 prize costs 16 cents because 80 divided by 5 = 16. And to get the cost of 50 prizes you do 16(50) = 800 cents. There are 100 cents in a dollar, giving you $8

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rodrigo is a salesman who earned a base pay of $38,800 and was paid commission of 14% for each book set he sold. If x represent
adoni [48]

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rodrigo will be getting be getting 5432 for his pay

Step-by-step explanation:


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3 years ago
PLEASE HELP!!! Write an equation for the following scenario.
alexandr402 [8]

Answer:2n + 8 = n-3

Step-by-step explanation:

7 0
3 years ago
-24+15-6=x
suter [353]

Answer:

x = -15

Step-by-step explanation:

-24 + 15 - 6 = x

-9 - 6 = x

-15 = x

4 0
3 years ago
Read 2 more answers
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0
3 years ago
Transform this equation to slope-intercept form: 6x + 4y = 8
JulsSmile [24]
Basically, ur just solving for y

6x + 4y = 8...subtract 6x from both sides
4y = -6x + 8....now divide both sides by 4
y = (-6/4)x + 8/4...reduce
y = -3/2x + 2 <=== slope intercept form
3 0
3 years ago
Read 2 more answers
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