Answer:
-8
Step-by-step explanation:
For roots r and s, the quadratic can be factored ...
f(x) = (x -r)(x -s) = x^2 -(r+s)x +rs
Then the value of r^2+s^2 can be determined from the coefficient of x (-(r+s)) and the constant (rs) by ...
r^2 +s^2 = (-(r+s))^2 -2(rs) = (r^2 +2rs +s^2) -2rs = r^2 +s^2
Comparing this to your given equation, we have the coefficient of x as (-2m) and the constant term as (m^2+2m+3). Forming the expression ...
(x-coefficient)^2 -2(constant term)
we get ...
r^2 +s^2 = (-2m)^2 -2(m^2 +2m +3) = 2m^2 -4m -6
r^2 +s^2 = 2(m -1)^2 -8
The minimum value of this quadratic expression is where m=1 and the squared term is zero. That minimum value is -8.
Answer:
6:0
Step-by-step explanation:
there is no bananas making it 0
Answer:
x = 4
Step-by-step explanation:
20x + 12 = 22x +4
12 - 4 = 22x - 20x
8 = 2x
4 = x
Answer:
1 hour and 17 minutiesstep explanation:
Your problem is giving you d in terms of t, meaning that it is asking if we replace t with 11, what would d be?
When a number is right in front of a variable, they are being multiplied
So if t is 11, and the problem shows 11t, we replace the t with 11 and put parentheses around it
d = -20 + 11t
d = -20 + 11(11)
d = -20 + 121
d = 101
And there you have it! Your final answer is d = 101!
Practice pre-algebra and plugging in numbers into equations! Having mastery over the basic math functions and rules, as well as Order Of Operations, makes all of this so much easier!
I recommend that you watch Khan Academy videos and practice problems on there! It is a great resource! What you are learning would most likely fall under pre-algebra!