we can divide the composite shape into on quadrilateral and triangle as shown in the diagram. since the line that joins the two shape is parallel to the base AB, the angle DEC is 85°.The angle CEA is 180°- angle DEC = 180-85=95. Angle BCE is sum of angle CEA, ABC and EAB subtracted from360°= 360°-(95+95+85)=85°. Angle DCE is 120°- ECB=35°. So, angle CDE = 180°-(35°+85°)= 60°. For reference see the diagram.
Here is my process for solving this.
First I drew arrows that indicated I was moving the whole triangle 5 units to the left.
*Look at first attachment*
Then I drew another triangle using those new points. (The new triangle is in pink)
*Look at second attachment*
Then I drew arrows that moved this new triangle 4 units up. (The new arrows are in pink)
*Look at third attachment*
Then I drew the new triangle in blue using the new points.
*Look at fourth attachment*
Then I mirrored / reflected the triangle over the x axis (the horizontal line) In green.
*Look at fifth attachment*
The fifth attachment in green is the final product! Hope that helps.
