<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B2x-5%7D%2B%20%5Cfrac%7B7%7D%7B3x%2B6%7D%3D12%20%20" id="TexFormula1" title

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3 years ago

=" \frac{3}{2x-5}+ \frac{7}{3x+6}=12 " alt=" \frac{3}{2x-5}+ \frac{7}{3x+6}=12 " align="absmiddle" class="latex-formula">

identify any domain restrictions

Mathematics

1 answer:

mestny [16]3 years ago

3 0

$D:2x-5 \not =0 \wedge 3x+6\not=0\\
D:2x \not =5 \wedge x+2\not=0\\
D:x \not =\frac{5 }{2} \wedge x\not=-2\\$

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Simplify (4x^-2y^3 ÷ xy^-4)^-2

Artyom0805 [142]

(‌4x−2y^3x‌y−4)−2
=‌x6y^8/16y^6‌
=‌x^6y^2/16

Hope this helps:)

6 0

3 years ago

Read 2 more answers

Rosia ate 1/8 of a pizza. She then split the remainder of the pizza so she could share with her friend. What fraction of the piz

Arturiano [62]

Answer:

7/16

Step-by-step explanation:

7 0

2 years ago

A principal of $2600 is invested at 7% interest, compounded annually. How much will the investment be worth after 13 years?

AveGali [126]

Answer:

The total amount accrued, principal plus interest, from compound interest on an original principal of $ 2600 at a rate of 7% per year compounded 1 time per year over 13 years is $ 6266.

Step-by-step explanation:

Given

Principle P = $2600

Interest rate r = 7% = 0.07

Time period t = 13 years

Compounded annually means: n = 1

To determine

Accrued Amount = ?

Using the formula

$A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}$

substituting P = 2600, r = 0.07, t = 13, n = 1

$A\:=\:2600\left(1\:+\:\frac{0.07}{1}\right)^{1\left(13\right)}$

$A=2600\left(1+0.07\right)^{1\cdot \:13}$

$A = 6266$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 2600 at a rate of 7% per year compounded 1 time per year over 13 years is $ 6266.

4 0

3 years ago

If f(x) = x2 − x − 12 and g(x) = x2 − 16, find f(x) × g(x).

Andreyy89

Answer:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

Step-by-step explanation:

We have the function f(x) = x^2 − x − 12 and g(x) = x^2 − 16 and we need to find the multiplication of both functions.

f(x) × g(x) = ( x^2 − x − 12)(x^2 − 16) = x^4 - 16x^2 -x^3 + 16x -12x^2 + 192

Simplifying:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

7 0