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2 years ago

14

Will give brainliest NEED HELP can some explain how to do this THANKS :D

1 answer:

arlik [135]2 years ago

3 0

Answer:

(x + 13, y + 7)

Step-by-step explanation:

Hello there!

In order to find what the translation rule is, we need to find how much it move to the right/left and up/down

In this case, the line segment VW moved up 7 and to the right by 13

We can get this by checking how far apart the points are

I checked how far apart V and V prime

(V prime is the green V. When a point is primed, its just saying that the point has gone through translation, rotation, dilation, or reflection)

V is 13 units to the left of V prime and 7 units below V prime

This means that, to go from line VW to line V prime W prime, you need to shift the line up 7 units and to the right 13 units

So, the translation rule is (x + 13, y + 7)

*If you don't understand, tell me in the comments, I will try to explain further to your understanding. Thank you, and have a great rest of your day :)*

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Lines parellel to the line 2x-1

tamaranim1 [39]

Answer:

2x-1

Step-by-step explanation:

5 0

3 years ago

K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

4 0

3 years ago

Diagram below shows the curve of a quadratic function

uranmaximum [27]

Answer:

q = -8, k = 2.

r = -6.

Step-by-step explanation:

f(x) = (x - p)^2 + q

This is the vertex form of a quadratic where the vertex is at the point (p, q).

Now the x intercepts are at -6 and 2 and the curve is symmetrical about the line x = p.

The value of p is the midpoint of -6 and 2 which is (-6+2) / 2 = -2.

So we have:

f(x) = 1/2(x - -2)^2 + q

f(x) = 1/2(x + 2)^2 + q

Now the graph passes through the point (2, 0) , where it intersects the x axis, therefore, substituting x = 2 and f(x) = 0:

0 = 1/2(2 + 2)^2 + q

0 = 1/2*16 + q

0 = 8 + q

q = -8.

Now convert this to standard form to find k:

f(x) = 1/2(x + 2)^2 - 8

f(x) = 1/2(x^2 + 4x + 4) - 8

f(x) = 1/2x^2 + 2x + 2 - 8

f(x) = 1/2x^2 + 2x - 6

So k = 2.

The r is the y coordinate when x = 0.

so r = 1/2(0+2)^2 - 8

= -6.

3 0

3 years ago

A number x divided by two is twelve.

gtnhenbr [62]

24 divide by two is 12
so x is 24

5 0

3 years ago

Read 2 more answers

An arithmetic sequence has this recursive formula: (a^1 =8, a^n= a^n-1 -6

eduard

Answer:

$a_n = 8 + (n - 1) (-6)$

Step-by-step explanation:

Given

$a_1 = 8$

Recursive: $a_{n} = a_{n-1} - 6$

Required

Determine the formula

Substitute 2 for n to determine $a_2$

$a_{2} = a_{2-1} - 6$

$a_{2} = a_{1} - 6$

Substitute $a_1 = 8$

$a_2 = 8 - 6$

$a_2 = 2$

Next is to determine the common difference, d;

$d = a_2 - a_1$

$d = 2 - 8$

$d = -6$

The nth term of an arithmetic sequence is calculated as

$a_n = a_1 + (n - 1)d$

Substitute $a_1 = 8$ and $d = -6$

$a_n = a_1 + (n - 1)d$

$a_n = 8 + (n - 1) (-6)$

Hence, the nth term of the sequence can be calculated using $a_n = 8 + (n - 1) (-6)$

3 0

3 years ago