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Ivenika [448]
3 years ago
9

Find the slope of the following (-5, -5), (-14, -9) (19,-6), (12, 20) (-14, 17), (14, 17)

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

1. m=4/9

2.m=-26/7

3.m=0

Step-by-step explanation:

Formula: Y=mx+b

1.y = 4 /9 x − 25 /9

2.y = − 26 /7 x + 452 /7

3.y=17

✨Hope this helps!✨

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Phantasy [73]

Answer:

D= -0.37

R= -0.34

Step-by-step explanation:

5 0
1 year ago
The two angles shown are complementary angles.What is the value of x?
astraxan [27]

Answer:

complementary angles are angles that sum up to 90 degrees. that is all I can say because I can't see any diagram

4 0
3 years ago
Read 2 more answers
Suppose the probability that a softball player gets a hit in any single at-bat is 0.300. Assuming that her chance of getting a h
Ksivusya [100]

Answer:

P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

X\sim Geo (1-p)

Solution to the problem

For this case we want this probability

P(X=4)

And using the probability mass function we got:

P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

4 0
3 years ago
Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0
choli [55]
Hello,
center is (4,-6)
radius=4
since
x^2-8x+y^2+12y+36=0\\

x^2-2*4x+16-16+y^2+2*6y+36=0\\

(x-4)^2+(y+6)^2=4^2




3 0
3 years ago
The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv
kari74 [83]
The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.

The mass of the particles moving in river is proportional to the sixth power of 2, or 2^6 = 64 miles per hour. So, if x is the mass of the particle, then the speed is modeled by an inverse relationship x * 2^6 = k, for some constant k. 

For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.

So, the key here is proportional. We can set up two proportions and cross multiply.

\dfrac{x}{2^6} =  \dfrac{15x}{y^6}  \\ (x)(y^6)=(2^6)(15x)

Cancelling our x's (because we don't need to solve for them), we have

y^6 = 15(2^6) = 15(64)=960

To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.

\sqrt[6]{y^6} =  \sqrt[6]{960}

Using a calculator, we see that \sqrt[6]{960} = 3.14 \ miles \ per \ hour.
6 0
4 years ago
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