Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
The perimeter is all the side lengths added up.
Add up all the side lengths:
6x - 4 + 6x - 4 + 12x + 3 + 12x + 3 + 14x + 13
Add all like terms.
50x + 11
The answer is C) 50x + 11 units
Answer:
Well first you put the y-intercept on the graph. In this case it would be 15
So graph the point (0,15)
The you do the slope which is 3
so you always do rise over run for slope.
If 3 were a fraction it would be 3/1 so go up 3 points and the go right 1 point from (0,15)
hope this helps .-.
