Answer:

Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

Plug -2 for one of the slopes.

Divide by -2 to find the slope of our line.

Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

Simplify and distribute:

Subtract 4 from both sides:

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
Answer:
2x - 1 = -45.
Step-by-step explanation:
2x - 1 = -45 is the required equation.
x is the number.
Answer:
f(x) = x² +x -6
Step-by-step explanation:
The standard form will look like ...
f(x) = x² +bx +c
where b is the opposite of the sum of the roots, and c is their product.
f(x) = x² -(-3+2)x +(-3)(2)
f(x) = x² +x -6
_____
<em>Additional comment</em>
In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).
Answer:
D
Step-by-step explanation:
A, B, and C are not linear functions
D would be y=x/2
If you graphed y=x/2, you would get the points (4, 2), (7, 3.5), (8, 4), and (10, 5)
It's more obvious if you notice that y is half of x.