A total of 35+21 = 56 tickets were sold. The probability of 5 men winning is the ratio
C(21, 5)/C(56, 5) = 20,349/3,819,816 ≈ 0.00533
_____
C(n, k) is the number of ways k items can be chosen from n items. Its value is
= n!/(k!*(n-k)!)
Answer:
(b) (a) (d) (a) (c)
Step-by-step explanation:
(i) The probability of an even card is 1/2 because the number of even cards and odd cards are the same so there is a 50% of getting an even card. (b)
(ii) Since the card is replaced, there is still a card for all numbers between 1-20. There are 8 prime numbers and 20 cards so the probability of getting a prime number is 8/20 or 4/10 or 2/5. (a)
(iii) The card was not replaced so there are only 19 cards and there are only 5 numbers that are multiples of 3 and greater than 4. The probability must be 5/19. (d)
(iv) A sure event means that it will happen 100%. So P(A) = 1 since the number one represents 100%. (a)
(v) All cards have replaced and there is only one number that is a multiple of 3 and 5 which is 15. 1 card out of 20 is a desired outcome so 1/20 is the probability. (c)
Answer:
The first number is 138.
Step-by-step explanation:
Let the first number be <em>x.</em>
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Then since they are consecutive numbers, the second number will be (<em>x</em> + 1), the third (<em>x</em> + 2), the fourth (<em>x</em> + 3) and the fifth being (<em>x</em> + 4).
We are given that their sum is 700. Therefore:

Solve for <em>x</em>. Combine like terms:

Subtract 10 from both sides:

Divide both sides by five. Therefore:

The first number is 138.
Answer:
Affects the width of a confidence interval, as the margin of error is a function of the sample standard deviation.
Step-by-step explanation:
When we have the standard deviation for the sample, the t-distribution is used to solve the question.
It does not affect the center of the interval, which is a function only of the sample mean.
Width of a confidence interval:
The width of a confidence interval is a function of the margin of error, which is:

In which s is related to the sample standard deviation. Thus, since s and M are directly proportional, a higher standard deviation makes the interval wider, lower standard deviation makes the interval narrower, and thus, the sample standard deviation affects the the width of a confidence interval.
Answer:
D. y=x^2-5
Step-by-step explanation: