The sides of the triangle would be 6 inches, 8 inches, and 9 inches long
Answer:
At least 198 chicken nuggets that measure quarter of a foot
Step-by-step explanation:
i went to mcdonalds got a s#!t ton of nuggs went to a road that no-body has driven in like 10 years and layed out 200 nuggets measured with a ruler 102 feet then drove my bike over themwith a camera recording in slow-mo looked at the tape and saw it was 32 revolutuions your welcome
Answer:
1. x= -b/a
2. x=b/a+c
3. x=b/a
4. x=a/-b+c
5. x= -a/b
6. x=c/a+b
7. x= -c/a+b
8. x=c/a-b
9. x=-b/c
10. x=a/b+c
11. x=c/-a+b
12. x= -c/b
13. x=a/-b+c
14. x= -c/a+b
15. x= -a/b+c
16. x=-a/-b+c
17. x= c/a+b
18. x= -c/a-b
19. x= -b/a+c
20. x=b/a+c
Step-by-step explanation:
Answer:
One
Step-by-step explanation:
Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)
To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.
Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.
When x is doubled, y is doubled. When z is multiplied by 5/8, so is y. The result of both changes is that y is multplied by 2·(5/8) = 5/4. The new value of y is
... y = 5/4·320 = 400
_____
If you really want to, you can use the formula
... y = kxz
and compute the value of k as
... k = y/(xz) = 320/(4·16) = 5
Then use this formula with the new values of x and z:
... y = 5·8·10 = 400
