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baherus [9]
3 years ago
7

How many different triangles can you make with the following conditions: angles measuring 45 degrees and 90 degrees and an INCLU

DED side that is 1 inch? one more than one none
Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

One

Step-by-step explanation:

Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)

To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.

Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.

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The hypotenuse of a right triangle is 5m long. The shorter leg is 1m shorter than the longer leg. Find the side lengths of the t
Vesna [10]

Answer:

Longer Leg = 5

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Hypotenuse = 169

Step-by-step explanation:

5 0
2 years ago
Solve for x 3x-1=9x+2
ANEK [815]
3x - 1 = 9x + 2

3x (-3x) - 1 (-2) = 9x (-3x) + 2 (-2)

-3 = 6x

-3/6 = 6x/6

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4 0
3 years ago
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For a certain horse race comma the odds in favor of a certain horse finishing in second placehorse race, the odds in favor of a
NikAS [45]

Answer:

0.33

Step-by-step explanation:

Let A denote an event. The odds of the horse finishing second is 33 to 67.

From the information, the total outcomes of event A is:

Total \ Outcomes, A=Favorable +Unfavorable\\\\=33+67\\\\=100

Hence, there are 100 total outcomes. The probability of the horse finishing second is calculated as:

p=\frac{n(A_f)}{n(A_u)}\\\\\\=p=\frac{33}{100}\\\\=0.33

Hence, the probability of finishing second is 0.33

7 0
3 years ago
Find:P(large or blue)
siniylev [52]

Answer:

7/10

Step-by-step explanation:

Total number = 17+3+8+12 = 40

The ones that are large are 17 and 8

The ones that are blue are 17 and 3

Do not count the 17 twice

P(large or blue) = (17+3+8)/40

                          = 28/40

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7 0
3 years ago
Help ASAP!!!!!!!!!!!!!!!!!!!!!!
Fittoniya [83]
The answer would be +3 since ur adding 3 every time
5 0
1 year ago
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