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solmaris [256]
3 years ago
8

Suppose you want to represent a triangle with sides 12 feet, 16 feet, and 18 feet on a drawing where 1 inch = 2 feet. How long s

hould the sides of the triangle be in inches?
The sides of the triangle on the drawing should be _____.
Mathematics
2 answers:
diamong [38]3 years ago
4 0
The sides of the triangle would be 6 inches, 8 inches, and 9 inches long
KengaRu [80]3 years ago
3 0

Answer: The sides of the triangle on the drawing should be <u>6 inches, 8 inches, and 9 inches</u>.

Step-by-step explanation:

Given: A triangle with sides 12 feet, 16 feet, and 18 feet on a drawing where 1 inch = 2 feet.

Then, 1 feet of original triangle =\frac{1}{2} inch on drawing.

Now, the sides of the triangle on the drawing are:-

12 feet =\frac{1}{2}\times12=6\text{ inches}

12 feet =\frac{1}{2}\times16=8\text{ inches}

12 feet =\frac{1}{2}\times18=9\text{ inches}

Hence, the sides of the triangle on the drawing should be 6 inches, 8 inches, and 9 inches.

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