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sveticcg [70]
3 years ago
12

Maria would like to answer the question “How cold is it in January in New York?”

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0
Statistics should be used because the temperature would vary during January and you would want to give an accurate answer.
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The graph shows two linear functions, f and g. Which formula BEST represents g(x)?
Softa [21]

Answer: C

g(x) = 1/2 f (x)

Step-by-step explanation:

3 0
3 years ago
Laden bought 10 bags of small marbles and 8 bags of large marbles.There were 12 marbles in each bag.How many Marbles did Karen b
mihalych1998 [28]

Answer:

216 marbles bought altogether

Step-by-step explanation:

small m- 10

large m- 8

10×12+8×12=

120+96

= 216

6 0
3 years ago
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Barry owns a music store, He recorded the sales of a newly launched album as part of his biweekly inventory. The table shows the
dimulka [17.4K]
Hi! Basically, the problem is asking us to find the values of a, b, and c in the equation f(x)=a x^{2} +bx+c. Since we have three unknowns, we just need three equations. We can find these equations by using the data in the table.

First let's plug x = 0 and f(x) = 0.
0=0+0+c
c=0

Now that we know c, it's time to pick two more pairs. Let's plug-in (2,78) and (4,152)

78=4a+2b
152=16a+4b

Before proceeding with the process of eliminating one variable, let us first reduce both equations to their lowest terms. We divide the first equation by 2 and we divide the second one by 4.

39=2a+b
38=4a+b

Next, we subtract equation 2 from equation 1.

1=-2a
a=-0.5

Finally, we substitute the value of a to equation 2 to get the value of b.

38=4(-0.5)+b
b=40

Therefore, the function should be f(x)=-0.5 x^{2} +40x
5 0
3 years ago
Read 2 more answers
Can someone help me?
Lana71 [14]

Answer:

I'm not sure from my answer but I'm going to try

A =  { a^2  -  4  = 0 }

A = { a^2  = 0+ 4 }

A = { a^2  = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= (  { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 }  ∩  { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

7 0
3 years ago
N/n^2-1 over 3n/n^2+8n+7
lisabon 2012 [21]

Answer:

B

Step-by-step explanation:

i did it

6 0
3 years ago
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