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3 years ago

14

What is the formula for average rate of change

2 answers:

djyliett [7]3 years ago

8 0

Answer:

(y2-y1)/(x2-x1)

step by-step explanation:

Average rate of change is just using the slope for...” Average rate of change is just using the slope formula: (y2-y1)/(x2-x1). It requires 2 points (ordered pairs).

emmasim [6.3K]3 years ago

3 0

Answer:

(y2-y1)/(x2-x1)

Step-by-step explanation:

Average rate of change is just using the slope formula: (y2-y1)/(x2-x1)

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Junior has a recipe that uses 1 3/4 cups of brown sugar and 3 1/3 cups of flour to make 18 muffins. He has a total of 10 cups of

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3 years ago

I'f a chef cooked 8 kilograms the guests ate 6/8 how much did they eat

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6 kilograms is the awnser

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3 years ago

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[Accessibility Mode

Hatshy [7]

Answer:

91 Adults

Step-by-step explanation:

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6 0

2 years ago

Steps to solve: 28x - 12 + 2x - 4 - x

Musya8 [376]

Let's simplify by step

28x-12+2x-4-x

28x+-12+2x+-4+-x

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28x+-12+2x+-4+-x

(28x+2x+-x)+(-12+-4)

29x+-16

= 29x-16

I hope that's help !

8 0

3 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0

2 years ago