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2 years ago

A rectangular piece of paper with length 35 cm and width 14 cm has two semicircles cut out of it, as shown below.

Mathematics

1 answer:

Ede4ka [16]2 years ago

3 0

Answer: 336.14 cm²

Step-by-step explanation:

To find the area of the rectangle after being cut, we want to find the area of the two semicircles and subtract it from the area of the rectangle. The area of the rectangle is just base times height, or 35cm times 14cm = 490cm² . Since there are two semicircles with the same diameter, we can just solve for the area of a circle and subtract it. To find the area of the circle, we need the radius, which we get by dividing the diameter by 2. After that, we calculate the radius to be 7cm, squared and multiplied by 3.14 (area of a circle) to get 153.86 cm². Subtract the areas, and we get 490 - 153.86 = 336.14 cm²

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A regular pentagon has an apothem of 7.3 inches and a perimeter of 53 inches. What is the area of the pentagon? Round your answe

zvonat [6]

Answer:

Area pf the regular pentagon is 193 $inch^{2}$ to the nearest whole number

Step-by-step explanation:

In this question, we are tasked with calculating the area of a regular pentagon, given the apothem and the perimeter

Mathematically, the area of a regular pentagon given the apothem and the perimeter can be calculated using the formula below;

Area of regular pentagon = 1/2 × apothem × perimeter

From the question, we can identify that the value of the apothem is 7.3 inches, while the value of the perimeter is 53 inches

We plug these values into the equation above to get;

Area = 1/2 × 7.3× 53 = 386.9/2 = 193.45 which is 193 $inch^{2}$ to the nearest whole number

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Answer:

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Step-by-step explanation:

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3 years ago

A number y increased by 5 is at least -21

gayaneshka [121]

- - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - - - - -

$\diamond\large\blue\textsf{\textbf{\underline{\underline{Given question:-}}}}$

❖ A number y increased by 5 is at least -21.

$\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}$

❖ First, if you come across the word "increased" it means we

"increase" a number, or add something to that number, like

y increased by 5 $\longmapsto$ $\sf{y+5}$

Now, we are also given that this expression is at least -21, which means it can't be -21; it can be -21 or it can be greater than -21.

So we have

$\longmapsto\sf{y+5\geq -21}}$

Solving for y

Subtract 5 on both sides:-

$\longmapsto\sf{y\geq -21-5}$

$\longmapsto\sf{y\geq -26}$

So the values of y greater than or equal to -26 will make this inequality true.

<h3>Good luck with your studies.</h3>

$\rule{300}{1}$

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