S=r*theta where s is arc length and the r is radius and theta is in RADIANS ONLY!! If you use degrees this formula does not work.
So we have a arc length of 38.485ft and a radius of 7. So rearranging the formula for theta, we get;
theta=(38.485)/(7)= 5.498radians then to convert to degrees if needed just take;
5.498rad*(180/pi)= 315deg
Answer:
15.86%
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Percent of area between the mean and 0.20 standard deviations from the mean:
pvalue of Z = 0.2 subtracted by the pvalue of Z = -0.2
Z = 0.2 has a pvalue of 0.5793
Z = -0.2 has a pvalue of 0.4207
0.5793 - 0.4207 = 0.1586
So this percentage is 15.86%
The correct question is
The composite figure is made up of a triangular prism and a pyramid. The two solids have congruent bases. What is the volume of the composite figure<span>
?</span>
the complete question in the attached figure
we know that
[volume of a cone]=[area of the base]*h/3
[area of the base]=22*10/2-------> 110 units²
h=19.5 units
[volume of a cone]=[110]*19.5/3------> 715 units³
[volume of a triangular prism]=[area of the base]*h
[area of the base]=110 units²
h=25 units
[volume of a a triangular prism]=[110]*25------------> 2750 units³
[volume of a the composite figure]=[volume of a cone]+[volume of a <span>a triangular prism]
</span>[volume of a the composite figure]=[715]+[2750]-------> 3465 units³
the answer is
The volume of a the composite figure is 3465 units³
Answer:
4) choice 1) 14.7 cm
5) choice 2) 14.8 cm
Step-by-step explanation:
4) 10^2 + 10^2 + 4^2 = 216
sq rt 216 = 14.7
5) 14^2 + 3^2 + 4^2 = 221
sq rt 221 = 14.86
If the width is w and the length is l, then 2w-2=l and 2w+2l=72 (using the perimeter equation). Plugging 2w-2 in for l, we get 2w+(2w-2)*2=72 and 6w-4=72. Adding 4 to both sides, we get 6w=76. After that, we divide both sides by 6 to get 74/6=w. Since l=2w-2=136/6, we get (136/6)(74/6)=656.75=area