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Aleks04 [339]
3 years ago
13

Solve for x-2a+7-3(-9-4a)​

Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0

Answer: a=-3.4

Step-by-step explanation: you mean solve for a:)

-2a+7-3(-9-4a)=0        We would have to equal this equation to 0

-2a+7+27+12a=0         We multiply the -3 with the parentheses

10a+34=0                     Add the like terms, and subtract 34 from both sides

10a=-34                        Then divide both sides by 10

a=-3.4

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Draw the graph of the line that is perpendicular to Y= 4X +1 and goes through the point (2, 3)
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Given:

\begin{gathered} y=4x+1 \\ \text{ point }(2,3) \end{gathered}

To find:

Draw a graph of a line that is perpendicular to the given line and passing through a given point.

Explanation:

As we know that relation between two slopes of perpendicular slopes of lines:

m_1.m_2=-1

Slope of given line y = 4x + 1 is:

m_2=4

So, the slope of line perpendicular to given line is:

m_2=-\frac{1}{4}

Also, so line equation that is perpendicular to given line is:

y=-\frac{1}{4}x+c...........(i)

Also, the required line is passing thorugh given point (2, 3), i.e.,

\begin{gathered} 3=-\frac{1}{4}(2)+c \\ c=3+\frac{1}{2} \\ c=\frac{7}{2} \end{gathered}

So, line equation that is perpendicular to given line is:

y=-\frac{1}{4}x+\frac{7}{2}

The required graph of line is:

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Step-by-step explanation:

3 x 7/4 - 203 x 54/5

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