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asambeis [7]
2 years ago
10

Whats 3 x 7/ 4 - 203 x 54/5???

Mathematics
1 answer:
Mice21 [21]2 years ago
7 0

Answer:

-2187.15

Step-by-step explanation:

3 x 7/4 - 203 x 54/5

21/4 - 10962/5

5.25 - 2192.4

-2187.15

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The circumference of a circle is 6 inches. What is the area of the circle?
Lubov Fominskaja [6]

Answer:

(B) 9π in²

Step-by-step explanation:

I’m going to assume that by 6 inches you meant 6π inches.

If the circumference of a circle is 6π inches, then it’s radius will be half of 6 (because the circumference of a circle is 2\pi r).

6\div2=3

So the radius is 3.

Now that we know the radius, we can find the area by using the equation \pi r^2.

\pi 3^2\\\pi9\\9\pi

Hope this helped!

3 0
3 years ago
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Perform the indicated operation.<br> 1/3÷3/8<br> A) 1/8<br> B)8/9<br> C)1 1/8
Alenkinab [10]

1/3÷3/8

Multiply by reciprocal

1/ 3÷ 8/3

Now multiply across


1×8/3×3


Solve

8/9


Your answer is b .


4 0
2 years ago
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Which of the following is an odd function?
irakobra [83]
F(x)=square root of x
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What is the cost of 1 pound of pears?
Ivahew [28]

Answer:

2.8

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5 0
3 years ago
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The sum of the squares of two consecutive positive integers is 41. Find the two
Komok [63]

We have to present the number 41 as the sum of two squares of consecutive positive integers.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

16 + 25 = 41

<h3>Answer: 4 and 5</h3>

Other method:

n, n + 1 - two consecutive positive integers

The equation:

n² + (n + 1)² = 41     <em>use (a + b)² = a² + 2ab + b²</em>

n² + n² + 2(n)(1) + 1² = 41

2n² + 2n + 1 = 41     <em>subtract 41 from both sides</em>

2n² + 2n - 40 = 0     <em>divide both sides by 2</em>

n² + n - 20 = 0

n² + 5n - 4n - 20= 0

n(n + 5) - 4(n + 5) = 0

(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0

n = -5 < 0 ∨ n = 4 >0

n = 4

n + 1 = 4 + 1 = 5

<h3>Answer: 4 and 5.</h3>
7 0
2 years ago
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