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Lyrx [107]
3 years ago
12

Use your understanding of the terms "soluble" and "insoluble" to explain why you must shake a bottle of salad dressing made with

oil and vinegar before you use it.
Chemistry
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

See explanation

Explanation:

In chemistry, the idea of "like dissolves like" is of utmost importance. A substance is only soluble in another with which it can effectively interact.

We must note that to be "soluble" means that the solute actually interacts effectively (dissolves) in the solvent.

However, vinegar is a polar substance while oil is a non polar substance hence the two can not effectively interact. That is, the vinegar can not dissolve in oil.

The two will separate into two phases upon standing. Therefore, the bottle of salad dressing made with oil and vinegar must be shaken in order to mix the two thoroughly before it is used.

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When a substance is heated ,the kinetic energy of its molecules
Simora [160]

Answer:

When a substance is heated ,the kinetic energy of its molecules also increase.

Explanation:

K.E is directly proportional to T

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Aluminum is often used in the structure of light-weight bicycle frames. How many
Brilliant_brown [7]

Answer:

The first thing that you need to do here is to figure out the mass of the sample.

To do that, you can use its volume and the fact that aluminium is said to have a density of

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5 0
2 years ago
Where the oxygen comes from the air (21% O2 and 79% N2). If oxygen is fed from air in excess of the stoichiometric amount requir
guajiro [1.7K]

Answer:

y_{O2} =4.3%

Explanation:

The ethanol combustion reaction is:

C_{2}H_{5} OH+3O_{2}→2CO_{2}+3H_{2}O

If we had the amount (x moles) of ethanol, we would calculate the oxygen moles required:

x*1.10(excess)*\frac{3 O_{2}moles }{etOHmole}

Dividing the previous equation by x:

1.10(excess)*\frac{3 O_{2}moles}{etOHmole}=3.30\frac{O_{2}moles}{etOHmole}

We would need 3.30 oxygen moles per ethanol mole.

Then we apply the composition relation between O2 and N2 in the feed air:

3.30(O_{2} moles)*\frac{0.79(N_{2} moles)}{0.21(O_{2} moles)}=121.414 (N_{2} moles )

Then calculate the oxygen moles number leaving the reactor, considering that 0.85 ethanol moles react and the stoichiometry of the reaction:

3.30(O_{2} moles)-0.85(etOHmoles)*\frac{3(O_{2} moles)}{1(etOHmoles)} =0.75O_{2} moles

Calculate the number of moles of CO2 and water considering the same:

0.85(etOHmoles)*\frac{3(H_{2}Omoles)}{1(etOHmoles)}=2.55(H_{2}Omoles)

0.85(etOHmoles)*\frac{2(CO_{2}moles)}{1(etOHmoles)}=1.7(CO_{2}moles)

The total number of moles at the reactor output would be:

N=1.7(CO2)+12.414(N2)+2.55(H2O)+0.75(O2)\\ N=17.414(Dry-air-moles)

So, the oxygen mole fraction would be:

y_{O_{2}}=\frac{0.75}{17.414}=0.0430=4.3%

6 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST
snow_tiger [21]

Answer:

I think it's B

Explanation:

I might be wrong, but please tell me.

5 0
2 years ago
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